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From: "Shobe, Dave" <dshobe@sud-chemieinc.com>
Subject: qcisd(t)--very strange
To: "'CCL'" <chemistry@ccl.net>
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Is it possible for the triples correction in qcisd(t) to leave the qcisd(t)
energy almost half a hartree higher than the qcisd energy?  
QCISD=-295.0176742 QCISD(T)=-294.5551278
These almost have to be different electronic states--but how did this
happen?  The molecule is CuF at R=1.7898 and (important hint?) this appears
to be one of those species that is poorly described by a single determinant.

--David Shobe


+++++++
 Iteration Nr.  31
 **********************
 DE(CORR)= -0.54044290D+00        E(CORR)=    -0.29501767435D+03
 NORM(A)=   0.25251768D+01
 Iteration Nr.  32
 **********************
 DE(CORR)= -0.54044284D+00        E(CORR)=    -0.29501767429D+03
 NORM(A)=   0.25251730D+01
 Iteration Nr.  33
 **********************
 DE(CORR)= -0.54044277D+00        E(CORR)=    -0.29501767422D+03
 NORM(A)=   0.25251714D+01
 Dominant configurations:
 ***********************
 Spin Case        I    J    A    B          Value
    AA            7        15           -0.622234D+00
    AA            7        18           -0.380065D+00
    AA            7        23           -0.239877D+00
    AA           14        15           -0.110013D+01
    AA           14        18           -0.640809D+00
    AA           14        19            0.138683D+00
    AA           14        23           -0.369077D+00
 Largest amplitude= 1.10D+00
 Time for triples=      253.00 seconds.
 T4(QCISD)= -0.33564626D+00
 T5(QCISD)=  0.79819266D+00
 QCISD(T)= -0.29455512782D+03

 **********************************************************************

            Population analysis using the SCF density.

 **********************************************************************

 Orbital Symmetries:
       Occupied  (SG) (SG) (SG) (PI) (PI) (SG) (SG) (PI) (PI) (DLTA)
                 (DLTA) (PI) (PI) (SG)
       Virtual   (SG) (PI) (PI) (SG) (SG) (PI) (PI) (SG) (SG) (PI)
                 (PI) (SG) (PI) (PI) (DLTA) (DLTA) (SG) (PI) (PI)
                 (SG) (PI) (PI) (SG) (DLTA) (DLTA) (PI) (PI) (SG)
                 (PI) (PI) (SG) (SG) (SG) (PI) (PI) (DLTA) (DLTA)
                 (PHI) (PHI) (DLTA) (DLTA) (PI) (PI) (SG) (SG)
  The electronic state is 1-SG.
 Alpha  occ. eigenvalues --  -26.13096  -5.07945  -3.41969  -3.41949
-3.41949
 Alpha  occ. eigenvalues --   -1.39304  -0.56693  -0.55033  -0.55033
-0.52642
 Alpha  occ. eigenvalues --   -0.52642  -0.46388  -0.46388  -0.44056
 Alpha virt. eigenvalues --   -0.01912   0.03765   0.03765   0.04025
0.06136
 Alpha virt. eigenvalues --    0.11920   0.11920   0.16392   0.22087
0.30468
 Alpha virt. eigenvalues --    0.30468   0.38673   0.38858   0.38858
0.41456
 Alpha virt. eigenvalues --    0.41456   0.43247   0.52223   0.52223
0.57931
 Alpha virt. eigenvalues --    0.73282   0.73282   0.79438   1.42810
1.42810
 Alpha virt. eigenvalues --    1.43659   1.43659   1.53722   1.63362
1.63362
 Alpha virt. eigenvalues --    1.69512   2.57754   4.28567   4.34819
4.34819
 Alpha virt. eigenvalues --    4.37817   4.37817   4.39725   4.39725
4.40072
 Alpha virt. eigenvalues --    4.40072   4.48642   4.48642   4.77192
6.70815
          Condensed to atoms (all electrons):
              1          2
  1  Cu  18.151326   0.149695
  2  F    0.149695   9.549284
 Total atomic charges:
              1
  1  Cu   0.698979
  2  F   -0.698979
 Sum of Mulliken charges=   0.00000
 Atomic charges with hydrogens summed into heavy atoms:
              1
  1  Cu   0.698979
  2  F   -0.698979
 Sum of Mulliken charges=   0.00000
 Electronic spatial extent (au):  <R**2>=   110.3634
 Charge=     0.0000 electrons
 Dipole moment (Debye):
    X=     0.0000    Y=     0.0000    Z=     6.7118  Tot=     6.7118
 Quadrupole moment (Debye-Ang):
   XX=   -15.4538   YY=   -15.4538   ZZ=   -20.4852
   XY=     0.0000   XZ=     0.0000   YZ=     0.0000
 Octapole moment (Debye-Ang**2):
  XXX=     0.0000  YYY=     0.0000  ZZZ=    22.4589  XYY=     0.0000
  XXY=     0.0000  XXZ=     4.5154  XZZ=     0.0000  YZZ=     0.0000
  YYZ=     4.5154  XYZ=     0.0000
 Hexadecapole moment (Debye-Ang**3):
 XXXX=   -11.1625 YYYY=   -11.1625 ZZZZ=   -94.9676 XXXY=     0.0000
 XXXZ=     0.0000 YYYX=     0.0000 YYYZ=     0.0000 ZZZX=     0.0000
 ZZZY=     0.0000 XXYY=    -3.7208 XXZZ=   -16.1866 YYZZ=   -16.1866
 XXYZ=     0.0000 YYXZ=     0.0000 ZZXY=     0.0000
 N-N= 5.055833589172D+01 E-N=-8.251139679182D+02  KE= 2.289446475560D+02
 Symmetry A1   KE= 1.404033163033D+02
 Symmetry A2   KE= 1.875292004753D+01
 Symmetry B1   KE= 3.489420560260D+01
 Symmetry B2   KE= 3.489420560260D+01
 1|1|UNPC-UNK|SP|RQCISD(T)-FC|Gen|Cu1F1|PCUSER|11-Dec-2000|0||#N QCISD(
 T) LANL2DZ EXTRABASIS||copper fluoride qcisd(t)//b3lyp/LANL2DZ++**||0,
 1|Cu|F,1,1.7898||Version=x86-Win32-G98RevA.9|State=1-SG|HF=-294.477231
 5|MP2=-295.0021973|MP3=-294.9326273|MP4D=-294.9593718|MP4DQ=-294.96448
 97|MP4SDQ=-294.9982426|QCISD=-295.0176742|QCISD(T)=-294.5551278|RMSD=7
 .342e-009|PG=C*V [C*(F1Cu1)]||@


 MARY HAD A LITTLE LAMB
      HIS FEET WERE BLACK AS SOOT,
           AND EVERYWHERE THAT MARY WENT
                HIS SOOTY FOOT HE PUT.

                    -- NONAME
 Job cpu time:  0 days  0 hours 25 minutes 46.0 seconds.
 File lengths (MBytes):  RWF=  116 Int=    0 D2E=    0 Chk=   11 Scr=    1
 Normal termination of Gaussian 98.



From chemistry-request@server.ccl.net  Tue Dec 12 11:33:46 2000
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Date: Tue, 12 Dec 2000 10:36:02 -0500
From: Joe Huang <jhuang@adrik.bchs.uh.edu>
To: CHEMISTRY@ccl.net
Subject: How to get the velocity informations in CHARMM?
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Dear CCLers,
We are trying to convert the velocities of the last step in
the CHARMM simulation(e.g., after 300 ps production run) into velocity pdb
format for NAMD2 program to continue the simulation without reassigning
the velocity. Does anybody know how to extract the velocity informations
from CHARMM run?
Your help will be much appreciated!!!


Joe
--

 ****************************************
 Hung-Chung (Joe) Huang, M.T., M.Sc.
 Department of Biology and Biochemistry
 University of Houston, Houston, TX 77204
 Tel: (713) 743-8389, Fax: (713) 743-8351
 e-mail: HCHuang@uh.edu
 http://adrik.bchs.uh.edu/~jhuang
 ****************************************


From chemistry-request@server.ccl.net  Tue Dec 12 12:42:07 2000
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Date: Tue, 12 Dec 2000 11:44:22 -0500
From: Joe Huang <jhuang@adrik.bchs.uh.edu>
To: CHEMISTRY@ccl.net
Subject: A question about CHARMM and T3E!
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Dear CCLers,
Recently, we got CHARMM(c27b3) from Harvard and tried to compile it in
Cray T3E at NPACI.
I compiled a MPI version successfully with the lib and include files under
the directory /opt/ctl/mpt/mpt in T3E.
But when I tried to run the CHARMM program in parallel, it looked like
it's always running in one CPU mode no matter how many computing nodes I
assign to the program. Can somebody tell me what I should do for this
problem? Thanks!!!

Joe
--

 ****************************************
 Hung-Chung (Joe) Huang, M.T., M.Sc.
 Department of Biology and Biochemistry
 University of Houston, Houston, TX 77204
 Tel: (713) 743-8389, Fax: (713) 743-8351
 e-mail: HCHuang@uh.edu
 http://adrik.bchs.uh.edu/~jhuang
 ****************************************


From chemistry-request@server.ccl.net  Tue Dec 12 12:57:04 2000
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Date: Tue, 12 Dec 2000 11:53:18 -0600
From: uddin@chem.wisc.edu
Subject: PVM error: libpvm [xxxxx]: pvmbeatask() pvmd didn't validate itself
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Hello,

When I try to run program ADF in parallel using PVM, I get the 
following error massage.

libpvm [xxxxx]: pvmbeatask() pvmd didn't validate itself
libpvm [xxxxx]: pvmbeatask() pvmd didn't validate itself
libpvm [xxxxx]: pvmbeatask() pvmd didn't validate itself
libpvm [xxxxx]: pvm_mytid() can't contact local daemon
NORMAL TERMINATION

My jobs terminates normally but use only one processor!
I would appreciate any suggestion.  Thanks in advance.


Jamal Uddin
Department of Chemistry
University of Wisconsin-Madison


 

From chemistry-request@server.ccl.net  Tue Dec 12 13:16:44 2000
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Date: Tue, 12 Dec 2000 13:15:52 -0500
From: "Shobe, Dave" <dshobe@sud-chemieinc.com>
Subject: comparing multireference energies
To: "'CCL'" <chemistry@ccl.net>
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 <157A51F55AAAD3119CD70008C7B1629DDAAB4F@lvlxch01.unitedcatalysts.com>
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Something has always bothered me about CASSCF and related multireference
methods.  Suppose you have a reaction such as Cu2 + F2 --> 2 CuF. CuF will
have some set of orbitals that belong in its active space, Cu2 will have
another set of orbitals for its active space, and F2 will have a single
active determinant.  So how does one compare energies to get the energy for
the given reaction?  

I hope (CAS)MP2 will be good enough for additional correlation.  Even if I
had a program that did MRCI, I doubt it would run on my little computer,
even for a diatomic.

--David Shobe






From chemistry-request@server.ccl.net  Tue Dec 12 15:21:41 2000
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Subject: Re: CCL:comparing multireference energies
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Hi,
One has to use the same number of correlated electrons and
orbitals to be able to compare energies. Even then, if the
composition of the active spaces (type of orbitals included) are
very differents from one species to another, results may be
unreliable.
CASMP2 (or CASPT2 or MRQDPT2) will correct this, but our
own excperience is that is is also a good idea to have a common
active space to perform single point calculations and obtain
reliable energies.

Ramon



"Shobe, Dave" wrote:

> Something has always bothered me about CASSCF and related multireference
> methods.  Suppose you have a reaction such as Cu2 + F2 --> 2 CuF. CuF will
> have some set of orbitals that belong in its active space, Cu2 will have
> another set of orbitals for its active space, and F2 will have a single
> active determinant.  So how does one compare energies to get the energy for
> the given reaction?
>
> I hope (CAS)MP2 will be good enough for additional correlation.  Even if I
> had a program that did MRCI, I doubt it would run on my little computer,
> even for a diatomic.
>
> --David Shobe
>
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