From owner-chemistry@ccl.net Thu Dec 23 08:00:01 2010 From: "Stephen Bowlus chezbowlus.:.comcast.net" <owner-chemistry_-_server.ccl.net> To: CCL Subject: CCL: calculation of logP using atom contribution Message-Id: <-43450-101222195651-7515-KozQ6m4B28buu3FJHUDn/g_-_server.ccl.net> X-Original-From: Stephen Bowlus <chezbowlus,+,comcast.net> Content-Type: multipart/alternative; boundary=Apple-Mail-18--921523408 Date: Wed, 22 Dec 2010 16:56:12 -0800 Mime-Version: 1.0 (Apple Message framework v936) Sent to CCL by: Stephen Bowlus [chezbowlus/./comcast.net] --Apple-Mail-18--921523408 Content-Type: text/plain; charset=US-ASCII; format=flowed; delsp=yes Content-Transfer-Encoding: 7bit What seems to work is the usual rules, supplemented by the rule: bonds to the same element don't count. In the usual formulation of the rules, this addition is a generalization of "elements have an oxidation state of 0" and is why the "exception" of oxygen = -1 in peroxides works. The only place this is addressed, as far as I know, is in general chemistry texts. The expanded rule can be justified on the basis that the electrons in a bond between the same elements are shared equally. One does get some wierdnesses depending on how the carbon is substituted, but the _change_ in oxidation states in the course of reaction seems reasonable. So the concept is successful as a bookkeeping method. One has to remember that it is the change in most cases that is physically relevant; otherwise, oxidation state is calculated on a completely non-physical basis. There is actually a nice Wikipedia article "Oxidation State" that shows situations as carbon's oxidation state varies from +4 (carbon tetrachloride) to -4 (methane). For an acetylene that you describe, I would calculate the oxidation state as -1. C-1 of propyne would be -1, C-2 would be 0 and C-3 would be -3. The four H's (a +1 each) make the molecule neutral. Steve On Dec 22, 2010, at 12:31 PM, Loan Huynh huynhkl2000 _ yahoo.ca wrote: > Dear CCL, > > I am currently calculating the logP values using the atom > contribution by Grosh and Crippen ( J. Computational Chemistry, > 1988, 9, p.80-90). > > > I have done quite a lot of searching on calculating the oxidation > state of carbon. However, I have trouble calculating the formal > oxidation number of various hybridization carbons. For example, for > H attached to sp carbon, I cannot obtain the formal charge of 3 for > sp carbon. > > > Is there any document that shows the calculation of oxidation number > for sp carbon? > > > Thank you very much for your help, > > > Loan > > > --Apple-Mail-18--921523408 Content-Type: text/html; charset=US-ASCII Content-Transfer-Encoding: quoted-printable <html><body style=3D"word-wrap: break-word; -webkit-nbsp-mode: space; = -webkit-line-break: after-white-space; ">What seems to work is the usual = rules, supplemented by the rule: bonds to the same element don't count. = In the usual formulation of the rules, this addition is a generalization = of "elements have an oxidation state of 0" and is why the "exception" of = oxygen =3D -1 in peroxides works. The only place this is = addressed, as far as I know, is in general chemistry texts. The expanded = rule can be justified on the basis that the electrons in a bond between = the same elements are shared equally.<div><br></div><div>One does get = some wierdnesses depending on how the carbon is substituted, but the = _change_ in oxidation states in the course of reaction seems reasonable. = So the concept is successful as a bookkeeping method. One has to = remember that it is the change in most cases that is physically = relevant; otherwise, oxidation state is calculated on a completely = non-physical basis.</div><div><br></div><div>There is actually a nice = Wikipedia article "Oxidation State" that shows situations as carbon's = oxidation state varies from +4 (carbon tetrachloride) to -4 (methane). = For an acetylene that you describe, I would calculate the = oxidation state as -1. C-1 of propyne would be -1, C-2 would be 0 = and C-3 would be -3. The four H's (a +1 each) make the molecule = neutral.</div><div><br></div><div>Steve</div><div><br><div><div>On Dec = 22, 2010, at 12:31 PM, Loan Huynh huynhkl2000 _ yahoo.ca wrote:</div><br = class=3D"Apple-interchange-newline"><blockquote type=3D"cite"><table = cellspacing=3D"0" cellpadding=3D"0" border=3D"0"><tbody><tr><td = valign=3D"top" style=3D"font: inherit;"><!--[if gte mso 9]><xml> = <w:WordDocument> <w:View>Normal</w:View> <w:Zoom>0</w:Zoom> = <w:Compatibility> <w:BreakWrappedTables/> <w:SnapToGridInCell/> = <w:WrapTextWithPunct/> <w:UseAsianBreakRules/> <w:UseFELayout/> = </w:Compatibility> = <w:BrowserLevel>MicrosoftInternetExplorer4</w:BrowserLevel> = </w:WordDocument> </xml><![endif]--><!--[if gte mso 10]> <style> /* = Style Definitions */ table.MsoNormalTable {mso-style-name:"Table = Normal"; mso-tstyle-rowband-size:0; = mso-tstyle-colband-size:0; mso-style-noshow:yes; = mso-style-parent:""; mso-padding-alt:0in 5.4pt 0in 5.4pt; = mso-para-margin:0in; mso-para-margin-bottom:.0001pt; = mso-pagination:widow-orphan; font-size:10.0pt; = font-family:"Times New Roman";} </style> <![endif]--><p = class=3D"MsoNormal">Dear CCL, <br> <br> I am currently calculating the = logP values using the atom contribution by Grosh and Crippen ( J. = Computational Chemistry, 1988, 9, p.80-90). </p><div> <br = class=3D"webkit-block-placeholder"></div><p class=3D"MsoNormal">I have = done quite a lot of searching on calculating the oxidation state of = carbon. However, I have trouble calculating the formal oxidation number = of various hybridization carbons. <span style=3D""> </span>For = example, for H attached to sp carbon, I cannot obtain the formal charge = of 3 for sp carbon.<span style=3D""> </span></p><div> <br = class=3D"webkit-block-placeholder"></div><p class=3D"MsoNormal">Is there = any document that shows the calculation of oxidation number for sp = carbon?<span style=3D""> </span></p><div> <br = class=3D"webkit-block-placeholder"></div><p class=3D"MsoNormal">Thank = you very much for your help,</p><div> <br = class=3D"webkit-block-placeholder"></div><p class=3D"MsoNormal">Loan</p> = <span style=3D"font-size: 12pt; font-family: "Times New = Roman";"></span><div = class=3D"plainMail"><br></div></td></tr></tbody></table><br></blockquote><= /div><br></div></body></html>= --Apple-Mail-18--921523408-- From owner-chemistry@ccl.net Thu Dec 23 11:28:01 2010 From: "William F. Coleman wcoleman:wellesley.edu" <owner-chemistry,+,server.ccl.net> To: CCL Subject: CCL: Calculation absorption spectrum using Gaussian G03 Message-Id: <-43451-101223100247-5565-hWQPKle1wTZm+Ifyzu6lMA,+,server.ccl.net> X-Original-From: "William F. Coleman" <wcoleman-,-wellesley.edu> Content-Type: multipart/alternative; boundary="--=_--22071c0a.22071b22.c939150c" Date: Thu, 23 Dec 2010 10:02:36 -0500 MIME-Version: 1.0 Sent to CCL by: "William F. Coleman" [wcoleman_._wellesley.edu] This is a multi-part message in MIME format. ----=_--22071c0a.22071b22.c939150c Content-Type: text/plain; charset=UTF-8 Content-Transfer-Encoding: 8bit An isolated gold atom is actually s1(d10f14), so I would check to make sure that the highest occupied orbital is predominately s in character, and proceed from there. Cheers, Flick _______________ William F. Coleman Professor of Chemistry Wellesley College Wellesley MA 02481 www.wellesley.edu/Chemistry/colemanw.html http://www.flicksstuff.com/photos/pictures.html new galleries 9/4/2010 Editor, JCE WebWare and JCE Featured Molecules http://www.jce.divched.org/JCEDLib/WebWare/ http://jchemed.chem.wisc.edu/JCEWWW/Features/MonthlyMolecules/index.html ----=_--22071c0a.22071b22.c939150c Content-Type: text/html; charset=UTF-8 Content-Transfer-Encoding: quoted-printable <?xml version=3D=221.0=22 encoding=3D=22UTF-8=22?> <=21DOCTYPE HTML PUBLIC =22-//W3C//DTD HTML 4.0 Transitional//EN=22> <html xmlns=3D=22http://www.w3.org/1999/xhtml=22> <head> <meta http-equiv=3D=22Content-Type=22 content=3D=22text/html; charset=3DUTF= -8=22 /> <title></title> <style type=3D=22text/css=22> <=21-- body=7Bmargin-left:10px;margin-right:10px;margin-top:10px;margin-bottom:10p= x;=7D --> </style> </head> <body marginleft=3D=2210=22 marginright=3D=2210=22 margintop=3D=2210=22 mar= ginbottom=3D=2210=22> <div align=3D=22left=22 style=3D=22text-align:left;=22><font face=3D=22Verd= ana=22 size=3D=22+1=22 color=3D=22=230000DD=22 style=3D=22font-family:Verda= na;font-size:14pt;color:=230000DD;=22>An isolated gold atom is actually s<s= up>1</sup>(d<sup>10</sup>f<sup>14</sup>), so I would check to make sure tha= t the highest occupied orbital is predominately s in character, and proceed= from there.</font></div> <br /> <div align=3D=22left=22 style=3D=22text-align:left;=22><font face=3D=22Verd= ana=22 size=3D=22+1=22 color=3D=22=230000DD=22 style=3D=22font-family:Verda= na;font-size:14pt;color:=230000DD;=22>Cheers,</font></div> <br /> <div align=3D=22left=22 style=3D=22text-align:left;=22><font face=3D=22Verd= ana=22 size=3D=22+1=22 color=3D=22=230000DD=22 style=3D=22font-family:Verda= na;font-size:14pt;color:=230000DD;=22>Flick</font></div> <br /> <br /> <div align=3D=22left=22 style=3D=22text-align:left;=22><font face=3D=22Verd= ana=22 size=3D=22+1=22 color=3D=22=230000DD=22 style=3D=22font-family:Verda= na;font-size:14pt;color:=230000DD;=22>_______________</font></div> <div align=3D=22left=22 style=3D=22text-align:left;=22><font face=3D=22Verd= ana=22 size=3D=22+1=22 color=3D=22=230000DD=22 style=3D=22font-family:Verda= na;font-size:14pt;color:=230000DD;=22>William F. Coleman</font></div> <div align=3D=22left=22 style=3D=22text-align:left;=22><font face=3D=22Verd= ana=22 size=3D=22+1=22 color=3D=22=230000DD=22 style=3D=22font-family:Verda= na;font-size:14pt;color:=230000DD;=22>Professor of Chemistry</font></div> <div align=3D=22left=22 style=3D=22text-align:left;=22><font face=3D=22Verd= ana=22 size=3D=22+1=22 color=3D=22=230000DD=22 style=3D=22font-family:Verda= na;font-size:14pt;color:=230000DD;=22>Wellesley College </font></div> <div align=3D=22left=22 style=3D=22text-align:left;=22><font face=3D=22Verd= ana=22 size=3D=22+1=22 color=3D=22=230000DD=22 style=3D=22font-family:Verda= na;font-size:14pt;color:=230000DD;=22>Wellesley MA 02481</font></div> <br /> <div align=3D=22left=22 style=3D=22text-align:left;=22><font face=3D=22Verd= ana=22 size=3D=22+1=22 color=3D=22=230000DD=22 style=3D=22font-family:Verda= na;font-size:14pt;color:=230000DD;=22><a href=3D=22http://www.wellesley.edu= /Chemistry/colemanw.html=22 target=3D=22_blank=22>www.wellesley.edu/Chemist= ry/colemanw.html</a></font></div> <div align=3D=22left=22 style=3D=22text-align:left;=22><font face=3D=22Verd= ana=22 size=3D=22+1=22 color=3D=22=230000DD=22 style=3D=22font-family:Verda= na;font-size:14pt;color:=230000DD;=22><a href=3D=22http://www.flicksstuff.c= om/photos/pictures.html=22 target=3D=22_blank=22>http://www.flicksstuff.com= /photos/pictures.html</a> new galleries 9/4/2010</font></div> <br /> <div align=3D=22left=22 style=3D=22text-align:left;=22><font face=3D=22Verd= ana=22 size=3D=22+1=22 color=3D=22=230000DD=22 style=3D=22font-family:Verda= na;font-size:14pt;color:=230000DD;=22>Editor, JCE WebWare and JCE Featured = Molecules</font></div> <div align=3D=22left=22 style=3D=22text-align:left;=22><font face=3D=22Verd= ana=22 size=3D=22+1=22 color=3D=22=230000DD=22 style=3D=22font-family:Verda= na;font-size:14pt;color:=230000DD;=22><a href=3D=22http://www.jce.divched.o= rg/JCEDLib/WebWare/=22 target=3D=22_blank=22>http://www.jce.divched.org/JCE= DLib/WebWare/</a></font></div> <div align=3D=22left=22 style=3D=22text-align:left;=22><font face=3D=22Verd= ana=22 size=3D=22+1=22 color=3D=22=230000DD=22 style=3D=22font-family:Verda= na;font-size:14pt;color:=230000DD;=22><a href=3D=22http://jchemed.chem.wisc= .edu/JCEWWW/Features/MonthlyMolecules/index.html=22 target=3D=22_blank=22>h= ttp://jchemed.chem.wisc.edu/JCEWWW/Features/MonthlyMolecules/index.html</a>= </font></div> <br /> <br/> </body> </html> ----=_--22071c0a.22071b22.c939150c-- From owner-chemistry@ccl.net Thu Dec 23 15:36:00 2010 From: "Loan Huynh huynhkl2000 : yahoo.ca" <owner-chemistry**server.ccl.net> To: CCL Subject: CCL: calculation of logP using atom contribution Message-Id: <-43452-101223120745-21624-SCGD2TGrDVTtUWtLMgZpKg**server.ccl.net> X-Original-From: Loan Huynh <huynhkl2000##yahoo.ca> Content-Type: multipart/alternative; boundary="0-1662746814-1293124058=:8922" Date: Thu, 23 Dec 2010 09:07:38 -0800 (PST) MIME-Version: 1.0 Sent to CCL by: Loan Huynh [huynhkl2000%%yahoo.ca] --0-1662746814-1293124058=:8922 Content-Type: text/plain; charset=utf-8 Content-Transfer-Encoding: quoted-printable =0A=0A=0A=0AHi Steve,=0A=0A=C2=A0=0A=0AThank you very much for your help. A= s you suggest, I did try=0Ato calculate the oxidation number base on genera= l rule (http://en.wikipedia.org/wiki/Oxidation_state).=0A=0A=0A=C2=A0=0A=0A= However, when I apply general rule for calculating formal=0Acharge of carbo= n, I can=E2=80=99t get the formal charge reported in Grosh and Crippen (=0A= J. Computational Chemistry, 1988, 9, p.80-90) paper.=0A=0A=C2=A0=0A=0AAccor= ding to Mannhold (J. Computer-Aided Molecular Design, 2001,=0A15, 337), Qui= nidine has 1 H that attached to Csp3 with formal charge of 0. It=0Aseem lik= e the general rule is not applicable to this case. =C2=A0=0A=0A=C2=A0=0A=0A= Then I try another method for calculating formal oxidation number. Accordin= g to Viswanadhan (J.=0AChem. Inf Comput. Sci. 1989, 29, 163), =E2=80=9Cthe = formal oxidation number of a carbon=0Aatom =3D sum of formal bond orders wi= th electronegative atoms=E2=80=9D, so H that=0Aattached to Csp3 with carbon= has formal charge of 3. However, Mannhold didn't report any functional gro= up that have 1H attached to Csp3 with carbon has formal charge of 3.=20 =0A=0A=C2=A0=0A=0AAny other suggestion is greatly appreciate. =0A=0A=C2=A0= =0A=0ALoan =0A=0A=C2=A0=0A=0A--- On Wed, 12/22/10, Stephen Bowlus chezbowlu= s.:.comcast.net <owner-chemistry]_[ccl.net> wrote: > From: Stephen Bowlus chezbowlus.:.comcast.net <owner-chemistry]_[ccl.net> Subject: CCL: calculation of logP using atom contribution To: "Huynh, Loan " <huynhkl2000]_[yahoo.ca> Received: Wednesday, December 22, 2010, 7:56 PM What seems to work is the usual rules, supplemented by the rule: bonds to t= he same element don't count. In the usual formulation of the rules, this ad= dition is a generalization of "elements have an oxidation state of 0" and i= s why the "exception" of oxygen =3D -1 in peroxides works. =C2=A0The only p= lace this is addressed, as far as I know, is in general chemistry texts. Th= e expanded rule can be justified on the basis that the electrons in a bond = between the same elements are shared equally. One does get some wierdnesses depending on how the carbon is substituted, b= ut the _change_ in oxidation states in the course of reaction seems reasona= ble. So the concept is successful as a bookkeeping method. One has to remem= ber that it is the change in most cases that is physically relevant; otherw= ise, oxidation state is calculated on a completely non-physical basis. There is actually a nice Wikipedia article "Oxidation State" that shows sit= uations as carbon's oxidation state varies from +4 (carbon tetrachloride) t= o -4 (methane). =C2=A0For an acetylene that you describe, I would calculate= the oxidation state as -1. =C2=A0C-1 of propyne would be -1, C-2 would be = 0 and C-3 would be -3. The four H's (a +1 each) make the molecule neutral. Steve On Dec 22, 2010, at 12:31 PM, Loan Huynh huynhkl2000 _ yahoo.ca wrote: Dear CCL,=20 =20 I am currently calculating the logP values using the atom contribution by = Grosh and Crippen ( J. Computational Chemistry, 1988, 9, p.80-90). =C2=A0 I have done quite a lot of searching on calculating the oxidation state of = carbon. However, I have trouble calculating the formal oxidation number of = various hybridization carbons. =C2=A0For example, for H attached to sp carb= on, I cannot obtain the formal charge of 3 for sp carbon.=C2=A0 =C2=A0 Is there any document that shows the calculation of oxidation number for sp= carbon?=C2=A0 =C2=A0 Thank you very much for your help,=C2=A0 Loan=20 =0A=0A --0-1662746814-1293124058=:8922 Content-Type: text/html; charset=utf-8 Content-Transfer-Encoding: quoted-printable <table cellspacing=3D"0" cellpadding=3D"0" border=3D"0" ><tr><td valign=3D"= top" style=3D"font: inherit;"><!--[if gte mso 9]><xml>=0A <w:WordDocument>= =0A <w:View>Normal</w:View>=0A <w:Zoom>0</w:Zoom>=0A <w:Compatibility>= =0A <w:BreakWrappedTables/>=0A <w:SnapToGridInCell/>=0A <w:WrapTextWi= thPunct/>=0A <w:UseAsianBreakRules/>=0A <w:UseFELayout/>=0A </w:Compat= ibility>=0A <w:BrowserLevel>MicrosoftInternetExplorer4</w:BrowserLevel>=0A= </w:WordDocument>=0A</xml><![endif]--><!--[if gte mso 10]>=0A<style>=0A /*= Style Definitions */=0A table.MsoNormalTable=0A=09{mso-style-name:"Table N= ormal";=0A=09mso-tstyle-rowband-size:0;=0A=09mso-tstyle-colband-size:0;=0A= =09mso-style-noshow:yes;=0A=09mso-style-parent:"";=0A=09mso-padding-alt:0in= 5.4pt 0in 5.4pt;=0A=09mso-para-margin:0in;=0A=09mso-para-margin-bottom:.00= 01pt;=0A=09mso-pagination:widow-orphan;=0A=09font-size:10.0pt;=0A=09font-fa= mily:"Times New Roman";}=0A</style>=0A<![endif]-->=0A=0A=0A=0A<p class=3D"M= soNormal">Hi Steve,</p>=0A=0A<p class=3D"MsoNormal"> </p>=0A=0A<p clas= s=3D"MsoNormal">Thank you very much for your help. As you suggest, I did tr= y=0Ato calculate the oxidation number base on general rule (<a href=3D"http= ://en.wikipedia.org/wiki/Oxidation_state">http://en.wikipedia.org/wiki/Oxid= ation_state</a>).=0A</p>=0A=0A<p class=3D"MsoNormal"> </p>=0A=0A<p cla= ss=3D"MsoNormal">However, when I apply general rule for calculating formal= =0Acharge of carbon, I can=E2=80=99t get the formal charge reported in Gros= h and Crippen (=0AJ. Computational Chemistry, 1988, 9, p.80-90) paper.</p>= =0A=0A<p class=3D"MsoNormal"> </p>=0A=0A<p class=3D"MsoNormal">Accordi= ng to Mannhold (J. Computer-Aided Molecular Design, 2001,=0A15, 337), Quini= dine has 1 H that attached to Csp3 with formal charge of 0. It=0Aseem like = the general rule is not applicable to this case. <span style=3D""> </s= pan></p>=0A=0A<p class=3D"MsoNormal"> </p>=0A=0A<p class=3D"MsoNormal"= >Then I try another method for calculating formal oxidation number. Accordi= ng to Viswanadhan (J.=0AChem. Inf Comput. Sci. 1989, 29, 163), =E2=80=9Cthe= formal oxidation number of a carbon=0Aatom =3D sum of formal bond orders w= ith electronegative atoms=E2=80=9D, so H that=0Aattached to Csp3 with carbo= n has formal charge of 3. However, Mannhold didn't report any functional gr= oup that have 1H attached to Csp3 with carbon has formal charge of 3. <br><= /p>=0A=0A<p class=3D"MsoNormal"> </p>=0A=0A<p class=3D"MsoNormal">Any = other suggestion is greatly appreciate. </p>=0A=0A<p class=3D"MsoNormal">&n= bsp;</p>=0A=0A<p class=3D"MsoNormal">Loan </p>=0A=0A<p class=3D"MsoNormal">= </p>=0A=0A--- On <b>Wed, 12/22/10, Stephen Bowlus chezbowlus.:.comcas= t.net <i><owner-chemistry]_[ccl.net></i></b> wrote:<br><blockquote styl= e=3D"border-left: 2px solid rgb(16, 16, 255); margin-left: 5px; padding-lef= t: 5px;"><br>From: Stephen Bowlus chezbowlus.:.comcast.net <owner-chemis= try]_[ccl.net><br>Subject: CCL: calculation of logP using atom contributio= n<br>To: "Huynh, Loan " <huynhkl2000]_[yahoo.ca><br>Received: We= dnesday, December 22, 2010, 7:56 PM<br><br><div id=3D"yiv863776987">What se= ems to work is the usual rules, supplemented by the rule: bonds to the same= element don't count. In the usual formulation of the rules, this addition = is a generalization of "elements have an oxidation state of 0" and is why t= he "exception" of oxygen =3D -1 in peroxides works. The only place th= is is addressed, as far as I know, is in general chemistry texts. The expan= ded rule can be justified on the basis that the electrons in a bond between= the same elements are shared equally.<div><br></div><div>One does get some wierdnes= ses depending on how the carbon is substituted, but the _change_ in oxidati= on states in the course of reaction seems reasonable. So the concept is suc= cessful as a bookkeeping method. One has to remember that it is the change = in most cases that is physically relevant; otherwise, oxidation state is ca= lculated on a completely non-physical basis.</div><div><br></div><div>There= is actually a nice Wikipedia article "Oxidation State" that shows situatio= ns as carbon's oxidation state varies from +4 (carbon tetrachloride) to -4 = (methane). For an acetylene that you describe, I would calculate the = oxidation state as -1. C-1 of propyne would be -1, C-2 would be 0 and= C-3 would be -3. The four H's (a +1 each) make the molecule neutral.</div>= <div><br></div><div>Steve</div><div><br><div><div>On Dec 22, 2010, at 12:31= PM, Loan Huynh huynhkl2000 _ yahoo.ca wrote:</div><br class=3D"yiv863776987Apple-interchange-newline"><blockquote type=3D"cite">= <table border=3D"0" cellpadding=3D"0" cellspacing=3D"0"><tbody><tr><td styl= e=3D"font: inherit;" valign=3D"top"><p class=3D"yiv863776987MsoNormal">Dear= CCL, <br> <br> I am currently calculating the logP values using the atom c= ontribution by Grosh and Crippen ( J. Computational Chemistry, 1988, 9, p.8= 0-90). </p><div> <br class=3D"yiv863776987webkit-block-placeholder"></= div><p class=3D"yiv863776987MsoNormal">I have done quite a lot of searching= on calculating the oxidation state of carbon. However, I have trouble calc= ulating the formal oxidation number of various hybridization carbons. <span= style=3D""> </span>For example, for H attached to sp carbon, I cannot= obtain the formal charge of 3 for sp carbon.<span style=3D""> </span= ></p><div> <br class=3D"yiv863776987webkit-block-placeholder"></div><p= class=3D"yiv863776987MsoNormal">Is there any document that shows the calcu= lation of oxidation number for sp carbon?<span style=3D""> </span></p><div> <br cla= ss=3D"yiv863776987webkit-block-placeholder"></div><p class=3D"yiv863776987M= soNormal">Thank you very much for your help,</p><div> <br class=3D"yiv= 863776987webkit-block-placeholder"></div><p class=3D"yiv863776987MsoNormal"= >Loan</p> <span style=3D"font-size: 12pt;"></span><div class=3D"yiv86377698= 7plainMail"><br></div></td></tr></tbody></table><br></blockquote></div><br>= </div></div></blockquote></td></tr></table><br> --0-1662746814-1293124058=:8922--