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From: Knegtel Ronald <r.knegtel@organon.oss.akzonobel.nl>
Subject: Cavities in complexes
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Dear all,

I would be interested to learn about software or subroutines that are
able to calculate the volume of cavities in protein-ligand complexes.
In other words, software that calculates the "empty volume" in between
the ligand and receptor. I'm aware of an option for this in MSI's Ludi
module but I would like to hear about stand-alone software, freeware,
algorithms etc. and especially tools that are fast.
Will summarize any replies.

Thanks,

Ronald

-------------------------------------------------------------------------------
Dr. Ronald M. A. Knegtel                     Research Scientist
Dept. of Molecular Design and Informatics    Phone  : +31-412-661469
N.V. Organon, RK2340                         Fax    : +31-412-662539
P.O. Box 20  5340 BH Oss                     http://www.organon.com/
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From chemistry-request@www.ccl.net  Thu Aug 20 12:03:44 1998
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Hi ccl'ers,
I am relatively new in the world of crystallography.  I have recently 
solved a structure of calix(4)arene in the hexagonal space group 
p63/m, with an Rfactor down to 5.83%.  The problem is that as yet I 
have not identified the solvent, initially I thought that it was 
acetonitrile, as I had three peaks, however the bond lengths vary are 
shorter than even a CN triple bond.  The atoms lie on special 
positions, but I am confused as to how to tackle this.
Any help would be much appreciated.
I have attached an output file from a shelxl refinement.


--Message-Boundary-12764
Content-type: text/plain; charset=US-ASCII
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Content-description: Text from file 'pyrxlcen.res'

TITL AL HYDROXY-CALIX-4-ARENE COMPLEX 27.7.98
CELL 0.71073  14.4788 14.4673 18.8024 89.8904 90.0331 119.9812
ZERR  6 .0013 .0041 .0121 0.361 0.02 0.0105
LATT 1
SYMM -Y, X-Y, Z
SYMM Y-X, -X, Z
SYMM -X, -Y, 0.5+Z
SYMM Y, Y-X, 0.5+Z
SYMM X-Y, X, 0.5+Z
SFAC C H O N
UNIT 168 144 24 0
L.S. 6
WGHT    0.078400    0.769600
EXTI    0.006795
FVAR       0.74488
O01     3  -0.00286   0.26856   0.15779  11.00000   0.05881   0.08170 =
        0.11258  -0.02072  -0.00765   0.03695
AFIX 143
H01     2   0.01965   0.32827   0.17463  11.00000  -1.50000
AFIX   0
C11     1  -0.07980   0.24927   0.10816  11.00000   0.05241   0.07996 =
        0.07552  -0.01632   0.01274   0.03315
C21     1  -0.09135   0.33352   0.08292  11.00000   0.05882   0.08038 =
        0.06184  -0.00233   0.01863   0.03284
C31     1  -0.16422   0.31155   0.02869  11.00000   0.07949   0.11218 =
        0.06112  -0.00448   0.00995   0.04587
AFIX  43
H31     2  -0.17313   0.36645   0.01058  11.00000  -1.20000
AFIX   0
C41     1  -0.22368   0.21068   0.00097  11.00000   0.09397   0.13605 =
        0.06702  -0.03410  -0.00713   0.04999
AFIX  43
H41     2  -0.27104   0.19797  -0.03614  11.00000  -1.20000
AFIX   0
C51     1  -0.21255   0.12884   0.02856  11.00000   0.08298   0.10804 =
        0.09646  -0.04985   0.00213   0.03862
AFIX  43
H51     2  -0.25378   0.06043   0.01024  11.00000  -1.20000
AFIX   0
C61     1  -0.14183   0.14565   0.08266  11.00000   0.06717   0.08412 =
        0.09980  -0.03518   0.01101   0.03945
C10     1  -0.13471   0.05266   0.11509  11.00000   0.07654   0.08115 =
        0.16269  -0.05289  -0.00016   0.04552
AFIX  23
H10A    2  -0.16442  -0.00643   0.08184  11.00000  -1.20000
H10B    2  -0.06026   0.07426   0.12220  11.00000  -1.20000
AFIX   0
O02     3  -0.03105   0.11806   0.25000  10.50000   0.05038   0.07552 =
        0.17967   0.00000   0.00000   0.03866
AFIX 143
H02     2  -0.01472   0.16060   0.21702  10.50000  -1.50000
AFIX   0
C12     1  -0.14028   0.04975   0.25000  10.50000   0.05136   0.05157 =
        0.16323   0.00000   0.00000   0.03611
C22     1  -0.19264   0.01518   0.18508  11.00000   0.06211   0.05206 =
        0.16098  -0.01797  -0.00067   0.03740
C32     1  -0.30215  -0.05649   0.18699  11.00000   0.07067   0.05457 =
        0.17493  -0.02320  -0.01040   0.03302
AFIX  43
H32     2  -0.33926  -0.08115   0.14444  11.00000  -1.20000
AFIX   0
C42     1  -0.35639  -0.09144   0.25000  10.50000   0.06350   0.05209 =
        0.20408   0.00000   0.00000   0.02510
AFIX  43
H42     2  -0.42954  -0.13858   0.25003  10.50000  -1.20000
AFIX   0
C20     1  -0.02780   0.44392   0.38553  11.00000   0.06170   0.06964 =
        0.06784  -0.01210  -0.01769   0.02654
AFIX  23
H20A    2   0.04529   0.46032   0.37888  11.00000  -1.20000
H20B    2  -0.02712   0.49522   0.41898  11.00000  -1.20000
AFIX   0
O04     3   0.05577   0.42890   0.25000  10.50000   0.04268   0.06751 =
        0.09729   0.00000   0.00000   0.02462
AFIX 143
H04     2   0.05342   0.39534   0.28580  10.50000  -1.50000
AFIX   0
C14     1  -0.03006   0.44687   0.25000  10.50000   0.03651   0.03895 =
        0.07141   0.00000   0.00000   0.01320
C24     1  -0.07096   0.45666   0.31491  11.00000   0.04805   0.04320 =
        0.06297  -0.00545  -0.00617   0.01681
C34     1  -0.15390   0.47827   0.31312  11.00000   0.06052   0.05100 =
        0.06705  -0.00777   0.00109   0.02710
AFIX  43
H34     2  -0.18233   0.48555   0.35567  11.00000  -1.20000
AFIX   0
C44     1  -0.19514   0.48920   0.25000  10.50000   0.05796   0.05473 =
        0.08090   0.00000   0.00000   0.03435
AFIX  43
H44     2  -0.25073   0.50394   0.24996  10.50000  -1.20000
AFIX   0
N1      1   0.33333   0.66667   0.25000  10.16667   0.20274   0.20274 =
        0.01890   0.00000   0.00000   0.10137
N2      1   0.33333   0.66667   0.30440  10.33333   0.16585   0.16585 =
        0.16177   0.00000   0.00000   0.08293
C4      1   0.40062   0.72871   0.34977  11.00000   0.44802   0.44705 =
        0.46619  -0.23905  -0.16872   0.23859
FMAP 2
PLAN -20
HKLF 4
END  
     
WGHT      0.0743      0.8687 
Q1    1  -0.6166 -0.2866  0.2500  10.50000  0.05    0.26
Q2    1  -0.0195  0.1900  0.1914  11.00000  0.05    0.25
Q3    1  -0.6039 -0.3039  0.3725  11.00000  0.05    0.20
Q4    1  -0.4980 -0.2480  0.2500  10.50000  0.05    0.18
Q5    1  -0.3333  0.3333  0.2500  10.16667  0.05    0.17
Q6    1  -0.0400  0.0622  0.1605  11.00000  0.05    0.17
Q7    1  -0.5625 -0.3125  0.3047  11.00000  0.05    0.16
Q8    1  -0.0400  0.0786  0.2934  11.00000  0.05    0.16
Q9    1  -0.4602 -0.5100  0.3466  11.00000  0.05    0.15
Q10   1  -0.2400  0.3461  0.2500  10.50000  0.05    0.15
Q11   1  -0.5355 -0.1955  0.3917  11.00000  0.05    0.14
Q12   1  -0.6400 -0.2274  0.3175  11.00000  0.05    0.14
Q13   1  -0.4520 -0.4220  0.3207  11.00000  0.05    0.14
Q14   1  -0.2600  0.2430 -0.0509  11.00000  0.05    0.14
Q15   1  -0.4619 -0.3619  0.2996  11.00000  0.05    0.14
Q16   1  -0.2300  0.0665  0.2500  10.50000  0.05    0.14
Q17   1  -0.1965  0.3400  0.1119  11.00000  0.05    0.13
Q18   1   0.0300  0.0113  0.5268  11.00000  0.05    0.13
Q19   1   0.0129  0.3929  0.1989  11.00000  0.05    0.13
Q20   1  -0.2700  0.4458  0.2975  11.00000  0.05    0.12

--Message-Boundary-12764--


From chemistry-request@www.ccl.net  Thu Aug 20 12:36:45 1998
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Date: Thu, 20 Aug 1998 09:36:04 -0700
From: "Paddy Kane" <p_kane@mailcity.com>
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 Hi,

 I have carried out conformarional searches on metal complexes of
 calixarenes - a class of macrocycle - by varying 15-20 torsional
 bonds per complex. I would like to carry out a population analysis
 based on the relative energy differences.

 However, I don't know what the degeneracy factors are for torsional
 states. Could anyone give me some advice (specific or general) on how
 to calculate these factors. 

 Kind rgds,
 Paddy.

---
Paddy Kane
School Of Chemical Sciences
Dublin City University
Glasnevin
Dublin 9
Ireland.

E-mail: p_kane@mailcity.com

Tel: 00-353-1-7045641
Fax: 00-353-1-7045503



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From chemistry-request@www.ccl.net  Thu Aug 20 13:10:34 1998
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From: Inge Muszynski <inge.muszynski@uni-tuebingen.de>
Subject: lone-pair-orientation in Furan




Dear CCL'lers,

I have got a question concerning the lone-pair-orientation of the oxygen in
Furan or in other 5-cycled heteroaromatic systems like 1,3,4-Thiadiazol etc.

Due to the planar character of Furan I would suppose a sp2-hybridisation for
the oxygen and an in-plane-orientation for its lone-pair. Surprisingly I
have found  an 0sp3 for Furan in the fragmental library of my molecular
modelling software SYBYL.

How to think about this?

Many thanks in advance.

Bye Inge Muszynski



From chemistry-request@www.ccl.net  Thu Aug 20 13:10:34 1998
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To: chemistry@www.ccl.net
From: Inge Muszynski <inge.muszynski@uni-tuebingen.de>
Subject: lone-pair-orientation in Furan




Dear CCL'lers,

I have got a question concerning the lone-pair-orientation of the oxygen in
Furan or in other 5-cycled heteroaromatic systems like 1,3,4-Thiadiazol etc.

Due to the planar character of Furan I would suppose a sp2-hybridisation for
the oxygen and an in-plane-orientation for its lone-pair. Surprisingly I
have found  an 0sp3 for Furan in the fragmental library of my molecular
modelling software SYBYL.

How to think about this?

Many thanks in advance.

Bye Inge Muszynski


From chemistry-request@www.ccl.net  Thu Aug 20 13:28:41 1998
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From: "Gustavo Moura" <gustavo@hathi.chem.pitt.edu>
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Dear CCL readers,
	after my last weeks summary I have received two more answers to the
question that I posted two weeks ago. Below you can find the two new answers
that I have received. My thanks to Darko Babic and James J. P. Stewart for
answering my question.
	Sincerely yours,
			Gustavo Moura
		   gustavo@hathi.chem.pitt.edu

Answer 1:

X-Sender: dbabic@rudjer.irb.hr
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	Hi!

	I thought you'll get many answers on this question and I didn't want
waste my time.  Probably many others thought the same, or it's the vacations
 ...

	There is no UNIQUE way of permuting orbitals in one sequence to match
the other one, but EACH way always includes either even or odd number of
transpositions.  This is all you have to know.  If there is an odd number of
permutations you must multiply the integral by -1, otherwise by +1.

	To determine the parity of the permutation, one may, for example,
count the number of inversions in it.  For each element in the permutation
count the number of preceding elements that are 'greater', and sum these
numbers up.  For example: |dbac> should be permuted to |abcd>.  Start with
the second element since there is NO element before the first one.  "b" is
the second element and it has "d" before it, which is 'greater' than "b",
so we start with 1.  "a" has two elements before: "d" and "b" and both are
'greater' than "a", so we add 2.  "c" has three elements before but only "d"
is 'greater' than "c", so we add 1 and the final result is 1+2+1=4=even.

	If the two sequences are not identical, say |abcd> and |bdaq>, you
can easily decide the ideal position of the different orbitals ("q" is to
be where "c" is), with some meaningless arbitrariness when they differ in
two orbitals.

	The above way of determining the permutation parity is not the only
one, but probably the most frequently used.

				Best wishes,
								Darko Babic
							Institute "Rudjer
Boskovic"
							HR-10001 Zagreb, POB
1016
								  Croatia

Answer 2:

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Dear Dr Moura,

The problem with determinants is also found in semiempirical
configuration interaction.  In the MOPAC 93 Manual, I describe
a procedure for bringing two (spin) determinants into maximum
coincidence, and working out the phase factor.

This problem is also given as FORTRAN code in the MECI function
of MOPAC.  However, it is not trivial...

Jimmy Stewart











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 Dear Colleague:

 Gaussian, Inc. is pleased to announce the availability of Gaussian 98, the
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From chemistry-request@www.ccl.net  Mon Aug 24 02:40:08 1998
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To: chemistry@www.ccl.net
From: Inge Muszynski <inge.muszynski@uni-tuebingen.de>
Subject: lone-pair-orientation in Furan





Dear CCL'lers,

I have got a question concerning the lone-pair-orientation of the oxygen in
Furan or in other 5-cycled heteroaromatic systems like 1,3,4-Thiadiazol etc.

Due to the planar character of Furan I would suppose a sp2-hybridisation for
the oxygen and an in-plane-orientation for its lone-pair. Surprisingly I
have found an 0sp3 for Furan in the fragmental library of my molecular
modelling software SYBYL.

How to think about this?

Many thanks in advance.

Inge Muszynski
Pharmaceutical Chemistry
University of Tuebingen
Auf der Morgenstelle 8
72076 Tuebingen



From chemistry-request@www.ccl.net  Mon Aug 24 05:24:02 1998
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Date: Mon, 24 Aug 1998 10:21:44 +0100
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From: "Nathaniel (noj) Malcolm" <mbdtsnm@mchhpf.ch.man.ac.uk>
To: kochw@argon.chem.tu-berlin.de
Cc: chemistry@www.ccl.net
In-Reply-To: <9808211425.AA42693@argon.chem.tu-berlin.de> (message from
	Wolfram Koch on Fri, 21 Aug 1998 16:25:07 +0200 (DFT))
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Wolfram,

	regarding your second two questions i highly reccomed you take
a look at :

(1)   TI: On the application of the Kohn-Sham theory to the calculation of 
          potential energy curves
      AU: Moscardo_F, PerezJimenez_AJ, SanchoGarcia_JC, SanFabian_E
      JN: CHEMICAL PHYSICS LETTERS, 1998, Vol.288, No.2-4, pp.418-422


This shows several examples of the failure of the single-determinant
KS results for simple reactions. ( generally they occur in
intermediate regions on the PES, UKS being OK at equilibrium and at
dissociation).  It also shows striking similarities between the 
RHF vs. UHf and RKS vs. UKS curves,

noj

-- 
Dr. Noj Malcolm			
Theory Group,			
Dept. of Chemistry,		
University of Manchester,	
Oxford Road,			
Manchester.			
M13 9PL

e-mail noj.malcolm@man.ac.uk                  




From chemistry-request@www.ccl.net  Mon Aug 24 10:42:04 1998
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Subject: Perturbation theory. A reference on computational aspects
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Greetings all, 

I wonder if anybody coud suggest a good reference regarding the
computational aspects of perturbation theory. As a matter I am a little
confused as regard the application of such a procedure using the results
of a Hartree-Fock calculation. 

Let me get more explicit : 

Let's assume for simplicity that one has a one-electron perturbation
H' = Sum_i h(i). Then, if my knowledge in this perturbation "business"
is right, the function~(first order correction) Psi' is expanded as a
linear combination of the determinants corresponding to the ground
state, first "excited" determinant, second "excited" determinanant, ...

This is the RSPT. 

As a consequence of this, the second order correction of the energy
should involve only the first "excited" determinant~(for a two particle
pertubation as in MP2 for instance we will use only the second "excited"
determinant.)

We know that the above expansion yields an exact answer if the basis set
is complete. 

The question is : Is there any procedure allowing us to choose the basis
functions in order to get accurate results though the size of the basis
is finite ? 

Thanks for your time and Help.
--
Ahmed


From chemistry-request@www.ccl.net  Mon Aug 24 14:14:14 1998
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From: "Md. Jamal Uddin" <jamal@chemie.uni-marburg.de>
To: chemistry@www.ccl.net
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Subject:       all electron or small-core ecp basis sets for Ga, In and Tl 
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Dear CCLer,

I am looking for small-core ecp basis sets and/or all electron basis sets for 
Ga, In, and Tl atoms in Gaussian format with references. 
Thanks in advance for kind help. 

Sincerely yours


Jamal Uddin

Philipps-Universitaet Marburg
Marburg, Germany

email: jamal@chemie.uni-marburg.de


