Subject: SUMMARY OF ANSWERS TO DIAGONALIZATION OF LAGRANGIAN MATRIX

From: "E. Lewars" <[email-masked]>
Date: Wed, 16 Dec 1998 18:59:52 -0500 (EST)

1998 Dec 15
              PAULING POINT
Thanks to all who replied to my question about diagonalizing the matrix of
undetermined Lagrangian multipliers in one derivation of the Hartree-Fock eqs.
Essentially I asked how do we know that this matrix _is_ diagonalizable (not all
square matrices are).
              E. Lewars

ANSWERS, MY SUMMARY (if any one has been omitted, it's my carelessness)

#1
Alan Shusterman
The matrix is Hermitian because its elements are integrals involving a Hermitian
operator (the Hamiltonian).

#2
Darko Babic
The matrix in my case is Hermitian.

#3
Eric Bittner
Think like this:
                      L = T -V
T and V are Hermitian, so L is Hermitian.
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