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Date: Sun, 16 May 1999 23:52:50 -0400 (EDT)
From: Jan Labanowski <jkl@ccl.net>
To: Christoph Maerker <maerker@chris2.u-strasbg.fr>
cc: chemistry@ccl.net, Jan Labanowski <jkl@ccl.net>
Subject: Re: apache server - htpasswd missing
In-Reply-To: <199905151641.SAA04271@chris2.u-strasbg.fr>
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On Sat, 15 May 1999, Christoph Maerker wrote:

> Universite Louis Pasteur
> Postal-Address: 4, rue Blaise Pascal, F- 67000 Strasbourg FRANCE
> Phone: +33/3-88-41-53-19
> Fax:   +33/3-88-60-63-83
> X-Mailer: ELM [version 2.4ME+ PL37 (25)]
> MIME-Version: 1.0
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> 
> Hi all,
> 
> I've got an apache www server. I want to passwd-protect some dirs,
> but the htpasswd command is missing. How can one create this command, please ?
> 
> Best regards,
> Christoph
> 


Dear Christoph,

The passwords for the .htaccess mechanism of controlling access to 
the directories are created by the same mechanism as for UNIX login,
i.e, /etc/passwd

If you do not have perl installed, you can just change your password
temporarily on the UNIX box by using
passwd
command
and then copy the password to the Web password file.

But this is cumbersome. The UNIX password is created with the crypt
routine. It consists of "seed" (first two characters of password)
and the encrypted password. The seed is composed of letters, digits,
and few other printable characters, and is a parameter (2nd) to the crypt
UNIX routine together with the "open text password" (1st). The crypt routine
returns seed and enctrypted password as a string.

encrypted_password = crypt(open_password, seed);

perl has a crypt function, so you could generate password by just typing this
at UNIX prompt:

perl
print STDOUT crypt("my_open_password", "7x"), "\n";
^D

7xUC7SQVQeS.U


Where, my_open_password, is the password which you want to encrypt,
7x is a seed (or salt, as people call it), ^D stands for CTRL/D, i.e,. 
end of transmission ASCII character, i.e, UNIX end of input. The
encrypted password will be 7xUC7SQVQeS.U in this case. While it is
so easy to generate encrypted password, there is no known way to
go from encrypted password to the unencrypted password beside doing
brute force checks and comparison with a dictionary (or guessted
password). Note that a person who knows encrypted password, knows
also the seed. Warning: you should not use the same passwords for
Web and for UNIX log in. UNIX will throw you out after few bad tries
and will make you wait. The Web usually will not punish password
cracking, and it is much easier to crack the Web password (essentially
unlimitted number of tries within short period of time) than the
UNIX password which punishes the wrong entry with a wait period.

Now, assuming that you want to use a script to make an encrypted password,
this will do it for you (save it, and give it  x permissions, and
put the right location of perl on the first line). It will also
generate a random seed for you.

-----------------  cut and save as make_passwd.pl ------------------
#!/usr/local/bin/perl

# generate encrypted password using the argument given
# Usage: make_passwd.pl password

@chars = ('a'..'z', 'A'..'Z', '0'..'9', '.', '/');

$n = $#chars + 1;
$n2 = $n*$n;

$seed = (time - $pid + (-s '/var/log/messages') + 1346235) % $n2;
$seed1 = int($seed / $n);
$seed2 = int($seed % $n);

$salt = $chars[$seed1] . $chars[$seed2];

if($#ARGV == 0) {
  $encpasswd = crypt($ARGV[0], $salt);
  }
else {
  die "Usage: make_passwd.pl plain_text_pass\n";
  }

print STDOUT "Encrypted Password = |$encpasswd|\n";
------------------ cut --------------


Example:

make_passwd.pl 'My*Secret'
Encrypted Password = |4v2FWV9S1AbyQ|

Your open password was My*Secret (the example does not imply that this
is the good password, it is actually one of the worst),
and the encrypted password in this case was 4v2FWV9S1AbyQ
(note, the 4v is the seed which program automatically created).

Now, how to protect your directory under Apache?
Assuming that the directories which you want to protect are allowed
in the Apache httpd.conf file to have password protection (e.g., if your
directories are under, say,  /web/private as in example below:

<Directory /web/private>
AllowOverride Limit AuthConfig Options
AuthType Basic
AuthName private-web
Options ExecCGI
</Directory>

you can protected them easily. In the directory, which you want to protect,
you place the file:
.htaccess
This file allows you to override some options from your httpd.conf
file. For example:

--------------- cut -----------
AuthUserFile /etc/httpd/auth/htpasswd
AuthGroupFile /etc/httpd/auth/htgroup
AuthName "For close friends only"
AuthType Basic

<Limit GET POST>
require group myfriends
</Limit>
------------ cut ---------

In the directory /etc/httpd/auth (or whatever you choose, but
do not put it in your Web tree), you create files htpasswd and htgroup
(or whatever names you want to give them). For example:

--------- cut: htpasswd ------------
jim:.lh4hjkcz.lFxE
joe:/wuDR9867DJNE
pipi:d/87ghkRTmIQ
-----------cut -------------------


-------- cut: htgroup -------------
myfriends:jim joe pipi
--------- cut -----------

The stuff which follows colon in httpasswd is encrypted password created
as described above. All files should be world readable.

Have fun, and remember that if you want to really protect stuff
which you serve over the Web, you need to use SSL protocol -- this
simple password protection does not encrypt communications, i.e.,
the passwords and the content. But SSL and ssleay is another story,
and cannot be described in a one-pager, it is slightly more complicated.


Jan K. Labanowski            |    phone: 614-292-9279,  FAX: 614-292-7168
Ohio Supercomputer Center    |    Internet: jkl@ccl.net 
1224 Kinnear Rd,             |    http://www.ccl.net/chemistry.html
Columbus, OH 43212-1163      |    http://www.ccl.net/

From chemistry-request@server.ccl.net  Mon May 17 00:54:27 1999
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	Mon, 17 May 1999 00:48:29 -0400 (EDT)
Date: Mon, 17 May 1999 00:48:29 -0400 (EDT)
From: Jan Labanowski <jkl@ccl.net>
To: Eric German <cermsge@techunix.technion.ac.il>
cc: chemistry@ccl.net, Jan Labanowski <jkl@ccl.net>
Subject: ab initio basis sets
In-Reply-To: <Pine.GSO.3.95.990516095010.18894A-100000@techunix.technion.ac.il>
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Hi CCL, can you give better answers than my naive explanations?
I did not look at these issues of ages...

Jan
jkl@ccl.net

Actually, your question is a good one for CCL, and you may want
to send it there to get opinions from experts in basis sets (I am not
an expert in any way). Also, I did not look at the papers...

My short comment:

1) Getting the good basis set is a a black art. While there is a systematic
   ways to get good basis sets (e.g., Dunning's correlation consistent basis
   sets), these sets are usually much larger than "ad hoc" (sorry, should be
   "intuitively optimized") basis sets.

2) You contract the inner s/p orbitals for at least 2 reasons:
    a) they usually do not change much on bonding, since most changes
       are in the valence orbitals
   
    b) to prevent core collapse -- the inner orbitals have VERY low
       energy (very large negative), and if uncontracted, the SCF
       optimization would first try to optimize coefficients for these
       orbitals rather than valence ones. 1% change in core orbital
       coefficient can make larger energy change for heavier elements than
       50% change in a valence orbital coefficient. So, it is safer to keep
       them contracted, since they are not optimial for molecular calculations
       as they are derived from atomic calculations.

3) How contractions are done... Again, it is an art... But in short,
   people can get accurate numeric Hartree-Fock atomic calculations
   and fit exponents and coefficients for gaussian expansion of numeric AOs.
   They can also vary exponents and coefficients for atomic calculations
   since these computations are computationally feasible. But when we go
   to molecules, we have to limit the basis set size, or it would not finish
   in our lifetime, and also, there are many molecules to try. So what people
   do, they try to pull together some basis functions (contract them) and redo
   the calculations using either atomic (most often) or simple/representative/
   molecular calculations to see how much energy they loose on going from
   uncontracted -> contracted. If energy change is small, contraction scheme
   is acceptable, if energy change is big, they try to come with different
   contraction scheme. And the big/small is in the eye of the beholder,
   and also depends on particular varian of ab initio (HF vs plethora of
   MCSCF and correlated methods) so often there are different contractions
   schemes for the same set of primitive gaussians. Note also that even for,
   say 20 primitive gaussians, you have a lot of possible contractions
   (factorials are involved), and rarely all possible contraction schemes
   are tried to see which one gives the lowest energy. So in many cases,
   there is a chance to design some new contraction scheme for the old set
   of primitive (i.e., uncontracted) gaussians. 


On Sun, 16 May 1999, Eric German wrote:

> 
> 
> 
> Dear Dr. Lobanowski,
>      I have not any  experience in using of ab initio basis sets  but I
> would like calculate complexes involving atoms of Pd.
>      I would greatly appreciate if you could clear me the following 
> problems with the contracted basis. Hay and Wadt have published
> (JCP,1985) the basis (3s3p4d) for Pd (see 1-st and 2-nd columns of
> table below. 
>  
> (3s3p4d)             [2s2p2d]       [2s1p1d]  
> ---------
> alpha_i   C_i           C_i            C_i
>  
> 5s-orbitals        
> 1                      1            1
> .4496  -.3594574     -1.166        -.3594574
> .1496   .5467561      1.6763        .5467561
>                        2            2
> .0436   .7414499      1.00          .7414499
> 5p-orbitals            
> 2-4                    3-5          3-5
> .7368   .03491         .0763285     .03491
> .0899   .4454769       .974006      .4454769
>                        6-8  
> .0262   .6611266      1.00          .6611266
> 4d-orbitals 
> 5-9                    9-13         6-10
> 6.091   .0447293       .0511957     .0447293
> 1.719   .4425814       .5506564     .4425814
> .6056   .5051035       .578125      .5051035
>                       14-18
> .1883   .2450132      1.00          .2450132
> 
> 9 basis funct.,   18 basis funct.,  10 basis funct.,
> 32 Gaussians      32 Gaussians      32 Gaussians
> 
> 2) There is the standard basis LANL1DZ in Gaussian94 for Pd. It is the
> contracted basis (3s3p4d)/[2s2p2q] (column 3 above). We see that this
> contraction increases the number of basis functions and increases CPU
> time. So, my question is: why this contraction is done and what is idea
> to do the contraction of the first and the second Gaussians but not, for
> example, of the first and the third for 5s-orbitals, and so for 5p
> Gaussians? Are the corresponding coefficients in column 3 obtained by the
> optimization procedure?
> 3) In Column 4 is given the contracted basis (3s3p4d)/[2s1p1d] 
> of Akinaga et al (J.Chem.Phys,109 (1988) 11010 ). We can see that the
> coefficients of this basis is the same as of the uncontracted basis 
> (3s3p4d). How do you think, what could be idea of this contraction?         
>     Many thanks in advance
>   
>               Best wishes
>                             Sicerely 
>                                          E.D. German
> 
> 

Jan K. Labanowski            |    phone: 614-292-9279,  FAX: 614-292-7168
Ohio Supercomputer Center    |    Internet: jkl@ccl.net 
1224 Kinnear Rd,             |    http://www.ccl.net/chemistry.html
Columbus, OH 43212-1163      |    http://www.ccl.net/

From chemistry-request@server.ccl.net  Mon May 17 03:32:32 1999
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Date: Mon, 17 May 1999 00:28:07 -0700 (PDT)
From: "Jesus M. Castagnetto" <jesusmc@scripps.edu>
Sender: jesusmc@scripps.edu
To: Christoph Maerker <maerker@chris2.u-strasbg.fr>
cc: ccl <chemistry@ccl.net>
Subject: Re: CCL:apache server - htpasswd missing
In-Reply-To: <199905151641.SAA04271@chris2.u-strasbg.fr>
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On Sat, 15 May 1999, Christoph Maerker wrote:
> Hi all,
> 
> I've got an apache www server. I want to passwd-protect some dirs,
> but the htpasswd command is missing. How can one create this command, please ?
> 
> Best regards,
> Christoph

Hi Christoph,

Jan gave you an script that will do the work of the program you ask for,
alternatively you could get one of the many pre-compiled distributions
of Apache (www.apache.org), which will contain the missing program. Or,
if your OS does not have a binary distribution, just get the source code 
and compile it. BTW, there are several free replacements in C code for
the same program.

Good luck.

--
Jesus M. Castagnetto <jesusmc@scripps.edu> - "Ken Zen Ichi-nyo"
Program Project:   http://www.scripps.edu/research/metallo/ 
Metalloprotein DB: http://metallo.scripps.edu/
Pilot Stuff: http://www.geocities.com/ResearchTriangle/Lab/1059/

From chemistry-request@server.ccl.net  Mon May 17 04:23:59 1999
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Date: Mon, 17 May 1999 10:06:20 +0100 (WETDST)
From: Jose Manuel Martinez Fernandez <josema@us.es>
To: chemistry@ccl.net
Subject: nucleotide structures using amber?
Message-Id: <Pine.HPP.3.91.990517095843.554A-100000@mozart.us.es>
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Dear Netters,

I'm trying to simulate single stranded DNA using
DL_POLY package. Force Field I'm using is AMBER
(JACS'95, vol. 117, 5179-5197)

In order to check if I correctly implemented the FF,
I would appreciate if anyone could send me optimized
structures obtained with other programs and their
corresponding energies using amber95. Just two or three
linked nucleotides I think is enough to test all the
terms.

thanks in advance,
josema


           __________________________________________________________
           _                                                        _
	   _     Jose Manuel Martinez Fernandez, Ph.D.              _
	   _  	Dept. de Quimica Fisica, Universidad de Sevilla     _
	   _  	Facultad de Quimica, SEVILLA 41012, SPAIN           _
	   _     e-mail:  jmmartin@cica.es                          _
	   _              josema@mozart.us.es                       _
           __________________________________________________________


            


From chemistry-request@server.ccl.net  Mon May 17 04:58:57 1999
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Date: Mon, 17 May 1999 01:32:52 -0700 (PDT)
From: "Carol Y.Y. Au" <carol@iris.chem.cuhk.edu.hk>
To: chemistry@server.ccl.net
Subject: Fermi Contact Contribution.
Message-ID: <Pine.SGI.3.91.990517005642.14779A-100000@iris>
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  This message is in MIME format.  The first part should be readable text,
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---1984092467-823873151-926575103=:9448
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Dear CCLers,

	I have used the keyword FIELD to calculate the Fermi Contact term 
        of water:  

	#P UHF/3-21G Field=F(2)30

        and I got the following results:

	Isotropic Fermi contact couplings:
	             1
	1  H    0.001198
	2  O   -0.433339
	3  H    0.001198

	Firstly, I would like to know what is the units of the above numbers 
since it is not stated in the G98 manual?

	According to J.A.Pople's paper, J. Chem. Phys.1968, 49, 
2960-2964, 2965-2970, 

	Jab = (h/2*PI)(8*PI*B/3)(8*PI*B/3)[(Ra*Rb)/lamda]
	 	*Summation Puv(u) <phi u |delta(r)| phi v>

 where B is the Bohr magneton,
       
       Ra and Rb are the magnetogyric ratio for nuclei a and b 
       respectively,
       
       lamda is the perturbation parameter,

       Puv(u) is the uvth element of the spin density matrix 
       evaluated at nucleus b,  			         

       delta(r) is the Dirac delta function at the position of the 
       nucleus a,

       phi u and phi v are atomic orbitals. 

	
	Finally, I would like to ask that the above numbers that I obtained
in the output file refers to which terms of the above equation?  

	Thank you for your kind attention.


Yours sincerely,

Carol Au
Nuclear Magnetic Resonance Group
Dept. of Chem. CUHK
E-mail :carol@iris.chem.cuhk.edu.hk
Phone  :(852) 2609 6167
Fax    :(852) 2603 5057





---1984092467-823873151-926575103=:9448--
From chemistry-request@server.ccl.net  Mon May 17 06:35:34 1999
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From: uccatvm <uccatvm@ucl.ac.uk>
Message-Id: <16578.199905171031@socrates-a.ucl.ac.uk>
Subject: Re: How to calculate BSSE of a 3-molecule system?
To: chemistry@server.ccl.net (CCL)
Date: Mon, 17 May 1999 11:31:07 +0100 (BST)
Cc: T.vanMourik@ucl.ac.uk (Tanja van Mourik)
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Hi Yubo,

To compute the interaction energy of a trimer ABC, the energy
of each fragment has to be calculated in the trimer basis set
{ABC}. In the Gaussian program package, one can simply achieve 
that by using the trimer basis set to compute the energy of A 
while "massaging" the nuclear charge of all atoms of molecules B 
and C to zero (and the same for the energies of B and C).

When you fully optimize the geometry of your system ABC, then you 
also have to take into account the monomer deformation energies
Udef, which is the energy required to bring a molecule X from its 
equilibrium geometry (re) to the geometry it has in the complex (rx). 
The equation for computing the counterpoise-corrected interaction
energy then becomes (in curly brackets the basis set used):

De(CP) = E(ABC){ABC} - E(A){ABC} - E(B){ABC} - E(C){ABC} +
         + Udef(A) + Udef(B) + Udef(C)

With Udef(X) = E(X){X}(rx) - E(X){X}(re)

You might also want to look at a recent discussion on CCL on BSSE in 
calc. of activation energies. Kalju Kahn summarized the discussion on 
the list. 

Hope this helps,

Tanja

-- 
  ====================================================================
     Tanja van Mourik                                                
                                      phone                               
     University College London        work:   +44 (0)171-504-4665   
     Christopher Ingold Laboratories  home:   +44 (0)1895-259-312    
     20 Gordon Street                 e-mail                         
     London WC1H 0AJ                  work: T.vanMourik@ucl.ac.uk 
     United Kingdom                   home: tanja@netcomuk.co.uk     
  ====================================================================
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In-reply-to: <Pine.HPP.3.91.990517095843.554A-100000@mozart.us.es> (message
	from Jose Manuel Martinez Fernandez on Mon, 17 May 1999 10:06:20 +0100
	(WETDST))
Subject: Re: CCL:nucleotide structures using amber?
References:  <Pine.HPP.3.91.990517095843.554A-100000@mozart.us.es>

> In order to check if I correctly implemented the FF,
> I would appreciate if anyone could send me optimized
> structures obtained with other programs and their
> corresponding energies using amber95. Just two or three
> linked nucleotides I think is enough to test all the
> terms.

It would be even better if someone could provide a publicly accessible
set of test cases. Test cases should be small systems in order to
simplify analysis, and provide as much information about individual
energy terms as possible. Ideally such a set of test cases should be
available for all the popular force fields.
-- 
-------------------------------------------------------------------------------
Konrad Hinsen                            | E-Mail: hinsen@cnrs-orleans.fr
Centre de Biophysique Moleculaire (CNRS) | Tel.: +33-2.38.25.55.69
Rue Charles Sadron                       | Fax:  +33-2.38.63.15.17
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France                                   | Nederlands/Francais
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Date: Mon, 17 May 1999 18:44:05 +0100
To: chemistry@server.ccl.net
From: "Dr. M. Biggs" <M.Biggs@surrey.ac.uk>
Subject: rule based determination of spectra
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Hi!

I am starting to look at the calculation of various spectra
(FTIR, RAMAN, NMR, X-ray, electron, neutron, EELS) based upon
a known molecular structure.

I would greatly appreciate some information on key reviews/texts
which talk about how to calculate spectra for a known molecular
structure using *rule-based approaches* (i.e. not QM calcs as I want
to look at many structures).

I am not sure such rule-based approaches exist but I suspect they
do and I have heard that atleast for FTIR they do as they are
available in commercial softwares.

I will summarize if you like.

Many Thanks in advance.

Regards,


Mark
e-mail: m.biggs@surrey.ac.uk


