From chemistry-request@ccl.net Wed Jul  2 12:57:02 2003
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Date: Wed, 02 Jul 2003 12:54:37 -0400
From: Su Wu <wusu(at)ele.uri.edu>
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To: Pradipta Bandyopadhyay <pradipta(at)cgl.ucsf.edu>,
   chemistry
 <chemistry(at)ccl.net>
Subject: Re: CCL:interpolation code for 3d data !!
References: <Pine.OSF.4.53.0307011638240.926103(at)adenine.cgl.ucsf.edu>
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Hi Pradipta,
I have done spline interpolation on x or y of A = f(x,y) in Matlab.  If 
interested, the following is some help information on spline, or go to
www.mathworks.com and search for 'spline'.
Good luck!
Su Wu

SPLINE Cubic spline data interpolation.
     YY = SPLINE(X,Y,XX) uses cubic spline interpolation to find YY, the 
values
     of the underlying function Y at the points in the vector XX.  The 
vector X
     specifies the points at which the data Y is given.  If Y is a 
matrix, then
     the data is taken to be vector-valued and interpolation is 
performed for
     each column of Y and YY will be length(XX)-by-size(Y,2).

     PP = SPLINE(X,Y) returns the piecewise polynomial form of the cubic 
spline
     interpolant for later use with PPVAL and the spline utility UNMKPP.

     Ordinarily, the not-a-knot end conditions are used. However, if Y 
contains
     two more values than X has entries, then the first and last value 
in Y are
     used as the endslopes for the cubic spline.  Namely:
        f(X) = Y(:,2:end-1),   df(min(X)) = Y(:,1),   df(max(X)) = Y(:,end)

     Example:
     This generates a sine curve, then samples the spline over a finer mesh:
         x = 0:10;  y = sin(x);
         xx = 0:.25:10;
         yy = spline(x,y,xx);
         plot(x,y,'o',xx,yy)

     Example:
     This illustrates the use of clamped or complete spline 
interpolation where
     end slopes are prescribed. Zero slopes at the ends of an 
interpolant to the
     values of a certain distribution are enforced:
        x = -4:4; y = [0 .15 1.12 2.36 2.36 1.46 .49 .06 0];
        cs = spline(x,[0 y 0]);
        xx = linspace(-4,4,101);
        plot(x,y,'o',xx,ppval(cs,xx),'-');

     See also INTERP1, PPVAL, SPLINES (The Spline Toolbox).


Pradipta Bandyopadhyay wrote:
> Hi,
> 
>   I am looking for a code(in fortran) for interpolation of a large set
> of 3 dimensional data (on an eqaully spaced grid). I tried the polynomial
> routine in numerical recipe -but it is very poor for my data. Probably
> spline or hermite polynomial based interpolation scheme would be the best.
> I would appreciate any help.
> 
> thanks.
> 
>          Pradipta
> 
> 
> 
> -= This is automatically added to each message by mailing script =-
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From chemistry-request@ccl.net Wed Jul  2 16:38:23 2003
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Date: Wed, 02 Jul 2003 15:38:17 -0500 (CDT)
From: Niharendu.Choudhury^at^mail.uh.edu
Subject: Ewald in CHARMM
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Hi all,
Thanks to all who answered me earlier.
I am in a new trouble.

I was initially running with following crystal keywords:

Crystal Define Cubic 24.850 24.850 24.850  90.0 90.0 90.0
Crystal Build noperations 0


and energy keywords :

ENERGY ATOM ELEC EWALD KAPPA 0.21  KMAX 4 KSQMAX 27 -
          CUTNB 10.0  CUTIM 10.0 CTOFNB 9.5  VDW SHIFT

it was running fine.


Now I have changed the energy section to the following:

ENERGY ATOM ELEC EWALD KAPPA 0.21  KMAX 4 KSQMAX 27 -
          CUTNB 12.0  CUTIM 12.0 CTOFNB 10  VDW SHIFT

and it is not running. (I have only changed cutnb and ctofnb, crystal section same).

Can anybody tell me why?

Bye
Niharendu Choudhury



From chemistry-request@ccl.net Tue Jul  1 23:02:14 2003
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From: "Telkuni" <telkuni)at(venus.dti.ne.jp>
To: <chemistry)at(ccl.net>
Subject: Re: How to get the orbital symmetry? -2
Date: Wed, 2 Jul 2003 11:57:34 +0900
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Jens, thanks for your kind reply.

To summarize your comment, I must start with proper 
structure for Gaussian symmetry recognition.

Now, I've just received a CCL message from Gaussian.Inc.
(also you've received)
It said that you should use "symm=loose" to the input.

So, I'll calculate with yours and Gaussian's method.


  Sincerely yours,
----------------------------------------------------
        Telkuni Tsuru     telkuni)at(venus.dti.ne.jp



----- Original Message ----- 
From: "Jens Spanget-Larsen" <spanget)at(virgil.ruc.dk>
To: "Telkuni" <telkuni)at(venus.dti.ne.jp>
Sent: Monday, June 30, 2003 11:00 PM
Subject: Re: CCL:How to get the orbital symmetry using Gaussian TDDFT ?


> Telkuni:
> 
> > With your words, must I continue the optimization until 
> > I have gotten the perfect nuclear coordinate?
> > If it is so, I'll modify the optimization step(s).
> 
> Dear Telkuni:
> 
> If you want Gaussian to recognize the symmetry elements of a 
> particular point group, you must make sure that the input 
> coordinates from the very beginning (that is, already in the 
> jobfile) are in perfect agreement with this symmetry. Then 
> Gaussian will adopt this symmetry, and the optimization 
> procedure will continue within that symmetry. So, if you are 
> convinced that your molecule possesses certain symmetry 
> properties, make sure that your input coordinates precisely 
> reflect this symmetry. 
> 
> In the present case, it is apparent from the input coordinates 
> of your jobfile that the compound in question is 2-methyl-
> anilin. If you want this molecule to posses a plane of 
> symmetry, corresponding to the input configuration, you must 
> make sure that the coordinates for the two hydrogens in 
> positions no. 13 and 15 are symmetrized:
> 
> H             2.583600      1.09939      0.89064
> H             2.583600      1.09939     -0.89064
> 
> and that the  z-coordinate of the hydrogen in position 14 is 
> equal to zero:
>  
> H             2.742198      -0.435063     0.00000
> 
> Then Gaussian will recognize a plane of symmetry, and 
> wavefunctions will be characterized according to the 
> irreducible representations of the Cs pointgroup. If you start 
> the calculation within this Cs geometry, the optimization will 
> continue within this symmetry, it cannot "break out".
> 
> However, the assumption of Cs symmetry is probably not 
> realistic for 3-methyl-aninlin. The equilibrium geometry of 
> this compound would not be expected to have any symmetry 
> elements at all (apart from the identity operation). The 
> pyramidalization of the NH2 group will destroy the molecular 
> plane of symmetry. - Also the conformation of the methyl group 
> in your input geometry seems problematic.
> 
> Jens >--<
> 
> 
> =-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=
> JENS SPANGET-LARSEN         Office:         +45 4674 2710
> Department of Chemistry     Fax:            +45 4674 3011
> Roskilde University (RUC)   Mobile:         +45 2320 6246
> P.O.Box 260                 E-Mail:        spanget)at(ruc.dk
> DK-4000 Roskilde, Denmark   http://virgil.ruc.dk/~spanget
> =-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=
> 
> 




From chemistry-request@ccl.net Wed Jul  2 06:56:04 2003
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Dear Ed,
In general, the accuracy of DFT under a basis set, depends on the =
functional
you are using and on the kind of species you are
working on, plus the property you are seeking (DFT is an aproximate =
method).
Generally it is not improved with the basis set.
Most articles I have read, use at least 6-31G*for every functional. If =
you
have decided your functional, look under what basis set it was =
parametrized.
 I hope I helped.

George Papamokos

----- Original Message -----
From: "Ed Brothers" <enb108)at(psu.edu>
To: <chemistry)at(ccl.net>
Sent: Tuesday, July 01, 2003 12:17 AM
Subject: CCL:Small basis set DFT.


> Folks:
>     Has anyone ever published a discussion of the accuracy of DFT at
> small basis sets?
>
> Ed.
> Merz group.
> Penn State.
>
>
> -=3D This is automatically added to each message by mailing script =
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<DIV>Dear Ed,<BR>In general, the accuracy of DFT under a basis set, =
depends on=20
the functional<BR>you are using and on the kind of species you =
are<BR>working=20
on, plus the property you are seeking (DFT is an aproximate=20
method).<BR>Generally it is not improved with the basis set.<BR>Most =
articles I=20
have read, use at least 6-31G*for every functional. If you<BR>have =
decided your=20
functional, look under what basis set it was parametrized.<BR>&nbsp;I =
hope I=20
helped.<BR><BR>George Papamokos<BR><BR>----- Original Message =
-----<BR>From: "Ed=20
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DFT.<BR><BR><BR>&gt; Folks:<BR>&gt;&nbsp;&nbsp;&nbsp;&nbsp; Has anyone =
ever=20
published a discussion of the accuracy of DFT at<BR>&gt; small basis=20
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From chemistry-request@ccl.net Wed Jul  2 01:36:52 2003
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From: Boris Gorelik <bgbg)at(pob.huji.ac.il>
To: CCL Mailing List <chemistry)at(ccl.net>
Subject: [SOLVED] CCL:Ambiguous rotation values
Date: Wed, 2 Jul 2003 08:36:24 +0000
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On Tue, 1 Jul 2003 17:53:48 -0400 Rick Venable wrote:
>It occurs to me that for a unit vector and it's inverse, and rotations
>of A that differ by pi, you will get the same relative orientation.
>Try just sampling A from 0 to pi

Yes, that was one part of the problem, but that was not all.
We changed the sampling of phi and theta (angles that define axis direction) 
to be from 0 to PI (thus limiting the axis direction to one hemisphere), but 
the problem was still present. Then we noted two points:
1. If A (the rotation angle) equals zero then every <phi, theta> combination 
will result in the same rotation (or should I say lack of rotation)
2. If the direction of the rotation axis is parallel to Z (theta==0), for a 
given A angle, all phi values will result in the same rotation.

Thanks for help
-- 
Boris Gorelik
-= ( 2*b || !(2*b)) That's the question =-
Wed, 02/Jul/2003, 2 Tamuz 5763
-------------------------------------------------
! Molecular Modelling Group !
! Pharmacy School, Hadassa Faculty of medicine !
! The Hebrew University of Jerusalem !
! http://www.md.huji.ac.il/models/group.html !
!
!------------------------------------------------




From chemistry-request@ccl.net Tue Jul  1 23:42:42 2003
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Date: Wed, 2 Jul 2003 11:42:37 +0800 (HKT)
Subject: Counterpoise problem of Gaussian03
From: "GAO Yi" <chgy)at(ust.hk>
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Dear CCLers,

I tried the Z-matrix and Cartesian coordinates in Gaussian98 and
Gaussian03, but the results are wrong for Guassian98, while Gaussian03
can't compute the counterpoise corrections of the separate parts for
all.Would you kindly give me some suggestions?

Best

Yi Gao
Department of Chemistry,
HKUST, HK

Below is the results of Gaussian03 program:

>> Input file (Z-matrix):
>> %mem=100mb
>> #p rb3lyp/6-31g(d) Counterpoise=2
>>
>> test
>>
>> 0 1 0 1 0 1
>>  C,0.0,0.0,0.0,1
>>  C, 1, B1,1
>>  C, 2, B2,1, A1,0,1
>>  C, 3, B3,2, A2, 1, D1,0,1
>>  S, 1, B4,2, A3, 3, D2,0,1
>>  H, 1, B5,2, A4, 3, D3,0,1
>>  H, 2, B6,1, A5, 5, D4,0,1
>>  H, 3, B7,2, A6, 1, D5,0,1
>>  H, 4, B8,3, A7, 2, D6,0,1
>>  C, 1, R1,2, A8, 3, D7,0,2
>>  C, 2, R1,1, A9,10, D8,0,2
>>  C, 3, R1,2,A10, 1, D9,0,2
>>  C, 4, R1,3,A11, 2,D10,0,2
>>  S, 5, R1,1,A12, 2,D11,0,2
>>  H,10,B14,1,A13, 2,D12,0,2
>>  H,11,B15,2,A14, 1,D13,0,2
>>  H,12,B16,3,A15, 2,D14,0,2
>>  H,13,B17,4,A16, 3,D15,0,2
>>
>>    B1             1.367442
>>    B2             1.429838
>>    B3             1.367442
>>    B4             1.736068
>>    B5             1.081675
>>    B6             1.084843
>>    B7             1.084842
>>    B8             1.081675
>>    B14            1.081675
>>    B15            1.084843
>>    B16            1.084842
>>    B17            1.081675
>>    A1           112.744698
>>    A2           112.744698
>>    A3           111.502553
>>    A4           128.421983
>>    A5           123.322645
>>    A6           123.932686
>>    A7           128.421983
>>    A8            90.000000
>>    A9            90.000000
>>    A10           90.000000
>>    A11           90.000000
>>    A12           90.000000
>>    A13           90.000000
>>    A14           90.000000
>>    A15           90.000000
>>    A16           90.000000
>>    D1             0.000000
>>    D2             0.000000
>>    D3           180.000000
>>    D4           180.000000
>>    D5           180.000000
>>    D6           180.000000
>>    D7           -90.000000
>>    D8             0.000000
>>    D9            90.000000
>>    D10           90.000000
>>    D11          -90.000000
>>    D12         -128.421983
>>    D13          123.322645
>>    D14          123.932686
>>    D15          128.421983
>>
>>    R1 3.0
>>
>> Output file:
>>
>>  Symmetry A'   KE= 5.487337134003D+02
>>  Symmetry A"   KE= 5.517851430966D+02
>>  No NMR shielding tensors so no spin-rotation constants.
>>  Leave Link  601 at Tue Jul  1 10:10:08 2003, MaxMem=   13107200 cpu:
>>      0.8 (Enter /usr/local/g03/l122.exe)
>>  Counterpoise: doing DCBS calculation for fragment   1 NewBq=T
>>  Leave Link  122 at Tue Jul  1 10:10:08 2003, MaxMem=   13107200 cpu:
>>      0.0 (Enter /usr/local/g03/l301.exe)
>>  Basis read from rwf:  (6D, 7F)
>>  No pseudopotential information found on rwf file.
>>  There are    87 symmetry adapted basis functions of A'  symmetry.
>> There are    87 symmetry adapted basis functions of A"  symmetry.
>> Integral buffers will be    262144 words long.
>>         Raffenetti 2 integral format.
>>  Two-electron integral symmetry is turned on.
>>    174 basis functions,   360 primitive gaussians,   174 cartesian
>> basis functio
>> ns
>>     22 alpha electrons       22 beta electrons
>>        nuclear repulsion energy       201.6692107959 Hartrees.
>>  IExCor= 402 DFT=T Ex=B+HF Corr=LYP ExCW=0 ScaHFX=  0.200000
>>  ScaDFX=  0.800000  0.720000  1.000000  0.810000
>>  IRadAn=      0 IRanWt=     -1 IRanGd=            0 ICorTp=0
>>  NAtoms=   18 NActive=   18 NUniq=    9 SFac= 5.66D+00 NAtFMM=   60
>> Big=F No density basis found on file   718.
>>  Leave Link  301 at Tue Jul  1 10:10:08 2003, MaxMem=   13107200 cpu:
>>      0.0 (Enter /usr/local/g03/l302.exe)
>>  NPDir=0 NMtPBC=     1 NCelOv=     1 NCel=       1 NClECP=     1
>> NCelD=      1
>>          NCelK=      1 NCelE2=     1 NClLst=     1 CellRange=     0.0.
>>  One-electron integrals computed using PRISM.
>>  One-electron integral symmetry used in STVInt
>>  NBasis=   174 RedAO= T  NBF=    87    87
>>  NBsUse=   174 1.00D-06 NBFU=    87    87
>>  Precomputing XC quadrature grid using
>>  IXCGrd= 2 IRadAn=           0 IRanWt=          -1 IRanGd=
>> 0.       NRdTot=    1114 NPtTot=      141812 NUsed=      146862 NTot=
>>      146878 NSgBfM=   173   173   173   173.
>>  Leave Link  302 at Tue Jul  1 10:10:10 2003, MaxMem=   13107200 cpu:
>>      1.8 (Enter /usr/local/g03/l303.exe)
>>  DipDrv:  MaxL=1.
>>  Leave Link  303 at Tue Jul  1 10:10:11 2003, MaxMem=   13107200 cpu:
>>      0.1 (Enter /usr/local/g03/l401.exe)
>>  Harris functional with IExCor=  402 diagonalized for initial guess.
>> ExpMin= 1.17D-01 ExpMax= 2.19D+04 ExpMxC= 3.30D+03 IAcc=1 IRadAn=
>>     1 Acc
>> Des= 1.00D-06
>>  HarFok:  IExCor= 402 AccDes= 1.00D-06 IRadAn=         1 IDoV=1
>>  ScaDFX=  1.000000  1.000000  1.000000  1.000000
>>  Spurious integrated density or basis function:
>>  NE=   44 NElCor=    0 El error=4.35D+01 rel=9.88D-01
>> Tolerance=1.00D-03 Shell    20     absolute error=3.21D-04
>>   Tolerance=1.20D-02 Shell    20       signed error=3.21D-04
>>     Tolerance=1.00D-01 Inaccurate quadrature in CalDSu.
>>  Error termination via Lnk1e in /usr/local/g03/l401.exe at Tue Jul  1
>> 10:10:14 2
>> 003.
>>  Job cpu time:  0 days  0 hours  4 minutes 30.1 seconds.





From chemistry-request@ccl.net Wed Jul  2 06:07:24 2003
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Date: Wed, 2 Jul 2003 12:07:22 +0200 (MEST)
From: Michel Petitjean <ptitjean[at]itodys.jussieu.fr>
Message-Id: <200307021007.h62A7M4X023838[at]ds10.itodys.jussieu.fr>
To: chemistry[at]ccl.net
Subject: CCL:Re: Ambiguous rotation values
X-Antivirus: scanned by sophie at shiva.jussieu.fr

To: CCL Mailing List <chemistry[at]ccl.net>
Subject: CCL:Re: Ambiguous rotation values

The relation between rotation matrix and axis+angle is usually
get from the quaternionic parametrization of the rotation,
rather than from the theta,phi,A system.
When you set theta=0 and phi=any_phi_value in:
a1x=sin(theta)*cos(phi),
a2x=sin(theta)*sin(phi),
a3x=cos(theta).
then you get (0,0,1) as direction of the axis, although I presume
that you would like to get independantly direction and angle.
The quaternionic formulation is available from numerous
textbooks and papers (e.g. J.Comput.Chem. 1995,16[1],80-90):
having a unit vector (p,a,b,c), where p=cos(angle/2) and
(a,b,c) is the direction, the rotation matrix R is:

    p^2+a^2-b^2-c^2    2*(ab-pc)        2*(ac+pb)
R =    2*(ab+pc)    p^2-a^2+b^2-c^2     2*(bc-pa)
       2*(ac-pb)       2*(bc+pa)     p^2-a^2-b^2+c^2

Conversely: p^2=(trace(R)+1)/4, and:

    a = ( R(3,2) - R(2,3) ) / 4p
    b = ( R(1,3) - R(3,1) ) / 4p
    c = ( R(2,1) - R(1,2) ) / 4p

Note also than (p,a,b,c) and (-p,-a,-b,-c) are the smae, and that
(a,b,c) is not a unit vector.
Sampling 3D rotations is get from random isotropically 3D directions
and random 2D angles (uniform law).
Regularly tessellated figures are sometimes used to get equally
spaced directions (e.g. from the vertices of the regular icosahedron),
but random sampling is much satisfacory for high number of points.

Michel Petitjean,                     Email: petitjean[at]itodys.jussieu.fr
ITODYS (CNRS, UMR 7086)                      ptitjean[at]ccr.jussieu.fr
1 rue Guy de la Brosse                Phone: +33 (0)1 44 27 48 57
75005 Paris, France.                  FAX  : +33 (0)1 44 27 68 14
http://petitjeanmichel.free.fr/itoweb.petitjean.html
http://petitjeanmichel.free.fr/itoweb.petitjean.freeware.html

Boris Gorelik <bgbg[at]pob.huji.ac.il> wrote:
>Dear All,
>We are trying to sample all possible rotations of a rigid ligand in a discrete 
>3D space. We define the rotation using a1x, a2x, a3x and A, where 
>(a1x,a2x,a3x) is the unit vector in the direction of the axis and A is the 
>angle of rotation in radians. The unit vector is defined by two degrees of 
>freedom namely: spherical angles theta and phi, and is calculated from them.
>We are using the rotate function from the BTL package 
>(http://bioinformatics.org/project/?group_id=184)
>Unfortunately, sometimes we get identical conformations, while using different 
>input to the function. How can this problem can be avoided?
>
>Every idea will be highly appreciated
>
>PS
>Some additional details:
>we use discrete value for phi, theta and A:
>0<phi<2*PI, 
>0<A<2*PI, 
>0<theta<PI
>
>a1x=sin(theta)*cos(phi),
>a2x=sin(theta)*sin(phi),
>a3x=cos(theta).
>
>The rotate function is based on the following rotation matrix:
>[cosA+a1x.a1x(1-cosA)      -a3xsinA+a1a2(1-cosA)	a2xsinA+a1xa3x(1-cosA) ]
>[a3xsinA+a1xa2(1-cosA)    cosA+a2xa2x(1-cosA)   	-a1xsinA+a2xa3x(1-cosA)]
>[-a2xsinA+a3xa1x(1-cosA)   a1xsinA+(1-cosA)a2xa3x 	cosA+(1-cosA)a3xa3x   ]
>-- 
>Boris Gorelik
>-= ( 2*b || !(2*b)) That's the question =-
>Sun, 29/Jun/2003, 30 Sivan 5763
>-------------------------------------------------
>! Molecular Modelling Group !
>! Pharmacy School, Hadassa Faculty of medicine !
>! The Hebrew University of Jerusalem !
>! http://www.md.huji.ac.il/models/group.html !
>!
>!------------------------------------------------


From chemistry-request@ccl.net Wed Jul  2 12:40:38 2003
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From: "Martijn Zwijnenburg" <M.A.Zwijnenburg*at*tnw.tudelft.nl>
Organization: Delft University of Technology (TNW-DCT)
To: chemistry*at*ccl.net
Date: Wed, 02 Jul 2003 18:40:24 +0200
MIME-Version: 1.0
Subject: ccl: 6-31G** basis-set in G98 for Ge
Message-ID: <3F032710.26615.2AF4C9FA@localhost>
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Hi,

I'm wondering were the 6-31G** basis-set for Ge in G98 originates 
from? Since I can only find 6-31G** basis-sets upto Zn at for 
instance the EMSL Basis Set Library site. Furthermore, it doesn't 
really strike me as 6-31G** (more functions, no f functions for 
polarization, see below). Anybody a guess?

Thanx in advance,

Martijn Zwijnenburg

****
 18 0
 S    8 1.00
  0.4890000000D+06  0.2220000000D-03
  0.7310000000D+05  0.1728000000D-02
  0.1664000000D+05  0.8950000000D-02
  0.4742000000D+04  0.3590500000D-01
  0.1569000000D+04  0.1128400000D+00
  0.5770000000D+03  0.2874800000D+00
  0.2290000000D+03  0.4344900000D+00
  0.9481000000D+02  0.3068300000D+00
 S    2 1.00
  0.2922000000D+02  0.4775900000D+00
  0.1245000000D+02  0.1114450000D+01
 S    1 1.00
  0.3642000000D+01  0.1000000000D+01
 S    1 1.00
  0.1502000000D+01  0.1000000000D+01
 S    1 1.00
  0.2462000000D+00  0.1000000000D+01
 S    1 1.00
  0.9209000000D-01  0.1000000000D+01
 P    6 1.00
  0.3596000000D+04  0.1442000000D-02
  0.8437000000D+03  0.1244200000D-01
  0.2662000000D+03  0.6469400000D-01
  0.9828000000D+02  0.2186650000D+00
  0.3993000000D+02  0.3933500000D+00
  0.1714000000D+02  0.4345300000D+00
 P    3 1.00
  0.7157000000D+01  0.2499750000D+00
  0.3068000000D+01  0.4693800000D+00
  0.1246000000D+01  0.2889600000D+00
 P    1 1.00
  0.2795000000D+00  0.1000000000D+01
 P    1 1.00
  0.8340000000D-01  0.1000000000D+01
 D    5 1.00
  0.7018000000D+02  0.2877000000D-01
  0.2007000000D+02  0.1552500000D+00
  0.7059000000D+01  0.3681400000D+00
  0.2553000000D+01  0.4657800000D+00
  0.8301000000D+00  0.2864800000D+00
 D    1 1.00
  0.2020000000D+00  0.1000000000D+01
 ****

----------------------------------------------------------------------
---
Martijn Zwijnenburg
Lab. of Applied Organic Chemistry and Catalysis
Delft University of Technology
Julianalaan 136
2628 BL Delft
The Netherlands
Tel: 0031-(0)152782691
Fax: 0031-(0)152784700
e-mail: M.A.Zwijnenburg*at*tnw.tudelft.nl
web page: http://come.to/tock




From chemistry-request@ccl.net Tue Jul  1 21:10:40 2003
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Date: Tue, 01 Jul 2003 21:10:11 -0400
From: "Peter Gannett" <pgannett$at$hsc.wvu.edu>
To: <chemistry$at$ccl.net>
Subject: Re: CCL:insightII/discover vs CHARMM
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Yao-Ying:

I am not a CHARMM user but do use a similar program - Amber.  I have
also used Insight.  There are pros/cons to either and it will depend on
your circumstances.  However, some pros/cons that come to mind are:

Insight costs a lot more than Charmm if you are at an academic
institution (ca $20,000 for Insight, less than $1000 for Charmm, last I
checked, $600).

Insight only runs in a serial environment, charm, I believe, runs in
either a serial or parallel mode.

Insight will offer tech service, charmm doesn't directly.  However, I
have not been impressed with Insight's tech service and listserves for
charmm are free and probably more helpful.

Insight has excellent graphics.

Both will solve protein/dna problems.  Which is better for either
problem is debatable.

Here's a third option to consider.  Get NAMD/VMD.  These programs will
do anything that Insight/CHARMM/Amber will do but NAMD/VMD are free.

Pete Gannett

>>> Yao-Ying Chien <chieny$at$pilot.msu.edu> 07/01/03 20:04 PM >>>
Hi,

Can someone tell me the pro's and con's of insightII/discover vs CHARMM?

I have used insightII/discover, but most people here seem to use CHARMM.
Wonder if you guys can explain for me the difference, in terms of the
pro's and con's? And if any reasons I should switch to CHARMM?

URL's discussing these are appreciated too.

Thanks,

Yao 


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From chemistry-request@ccl.net Wed Jul  2 13:19:35 2003
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Date: Thu, 3 Jul 2003 01:19:02 +0800 (CST)
From: =?gb2312?q?Jinsong=20Zhao?= <zh_jinsong)at(yahoo.com.cn>
Subject: CCL: Re: About octanol/water partition coefficient (Kow)
To: CCL <chemistry)at(ccl.net>
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I should make it more clear. I hope to know methods
that could be used to predict the Kow of two or more
organic chemicals that are solved in the 
octanol/water system at the same time. 

I mean I hope to know the Kow of a mixture consisting 
of two or more organic chemicals if I know the
fraction of each chemicals.

Many thanks to the response to my previous questions.

Regards,

Jinsong

 --- Jinsong Zhao <zh_jinsong)at(yahoo.com.cn> :
> Dear all,
> 
> As you know, now the octanol/water partition
> coefficient, i.e., Kow, could be calculated using
> many
> programs. 
> 
> However, those softwares just give the Kow of a
> sigle
> organic chemical in the octanol/water system. I am
> very interested in the prediction for the Kow of two
> or more organic chemicals in such system. 
> 
> Is it possible to do the prediction? Any suggestions
> or comments will be welcome!
> 
> Thanks in advance!
> 
> Regards,
> 
> Jinsong
> 

_________________________________________________________
Do You Yahoo!? 
MxA55DZ9JM#:UfGi;9JG7EW]#?
http://cn.rd.yahoo.com/mail_cn/tag/?http://cn.surveys.yahoo.com/netlove


From chemistry-request@ccl.net Wed Jul  2 01:28:55 2003
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Date: Wed, 02 Jul 2003 07:28:48 +0200
From: Andreas Klamt <klamt*at*cosmologic.de>
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To: Jinsong Zhao <zh_jinsong*at*yahoo.com.cn>, CHEMISTRY <CHEMISTRY*at*ccl.net>
Subject: Re: CCL:About octanol/water partition coefficient (Kow)
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To be honest, I do not exactly understand what you are looking for. But
our COSMOtherm program (see www.cosmologic.de) is able to predict
general partition coefficients of almost arbitrary organic compounds
between almost arbitrary phases at variable temperature, just based on
quantum chemical calculations.

Andreas

Jinsong Zhao wrote:

>Dear all,
>
>As you know, now the octanol/water partition
>coefficient, i.e., Kow, could be calculated using many
>programs. 
>
>However, those softwares just give the Kow of a sigle
>organic chemical in the octanol/water system. I am
>very interested in the prediction for the Kow of two
>or more organic chemicals in such system. 
>
>Is it possible to do the prediction? Any suggestions
>or comments will be welcome!
>
>Thanks in advance!
>
>Regards,
>
>Jinsong
>
>_________________________________________________________
>Do You Yahoo!? 
>MxA55DZ9JM#:UfGi;9JG7EW]#?
>http://cn.rd.yahoo.com/mail_cn/tag/?http://cn.surveys.yahoo.com/netlove
>
>
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>
>
>
>
>
>  
>

-- 
--------------------------------------------------------------------------------
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From chemistry-request@ccl.net Wed Jul  2 10:28:47 2003
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2003 July 1

Re "Has anyone ever published a discussion of the accuracy of DFT at
small basis sets?"

I'm not sure just what you consider small (most workers now would likely
say that
6-31G* is small), but DFT calculations are known to be saturated by
basis
functions more quickly than are ab initio calculations. Here are three
refs:

1)  "Once the double split-valence level is reached, further improvement
in basis
set quality offers little in the way of structutal or energetic
improvement." G.
N. Merrill, S. Gronert, and S. R. Kass. J Phys Chem, 1997, _101_, 204.

2)  "Our results also show that B3LYP calculations converge rapidly with

increasing basis set size and that the cost-to-benefit- ratio is optimal
at the
6-31G* basis set level. 6-31G* will be the basis set of choice in B3LYP
calculations on much larger molecules [than C4H6O2]." P. J. Stephens, F.
J.
Devlin, C. F. Chablowski, and M. J. Frisch, J Phys Chem, 1994, _98_,
11623, and
refs therein.

3)  In defiance of tradition, the unequivocally small 3-21G(*) set has
been used
to optimize carbene geometries: H. M. Muchall, N. H. Werstiuk, and B.
Chodhurry,
Can J Chem, 1998, _76_, 221.

(You my also find some useful info in E. Lewars, "Computational
Chemistry",
Kluwer, 2003; section 7.3.2.2).

E. Lewars
========

Ed Brothers wrote:

> Folks:
>     Has anyone ever published a discussion of the accuracy of DFT at
> small basis sets?
>
> Ed.
> Merz group.
> Penn State.
>



From chemistry-request@ccl.net Tue Jul  1 22:32:00 2003
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From: Vivek Raut <vivek_clemson(at)yahoo.com>
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Can Tinker be used for parallel processing, if yes then how efficient is it than say GROMACS?.. if no , then how likely this feature will be incorporated in Tinker??
 


 - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - 
Vivek Raut
Graduate Research Assistant
Dept. of Bioengineering
Clemson University, SC- 29631.
Email:vraut(at)clemson.edu
Phone: 864-650-1431





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<DIV>Can Tinker be used for parallel processing, if yes then how efficient is it than say GROMACS?.. if no , then how likely this feature will be incorporated in Tinker??</DIV>
<DIV>&nbsp;</DIV><BR><BR><DIV>
<DIV>
<DIV>
<DIV><FONT face=verdana>&nbsp;- - - - - - - - - - -&nbsp;- - - - - - - - - - - - - - - - - - - - - - - - </FONT></DIV>
<DIV><FONT face=Verdana color=#0000ff>Vivek Raut</FONT></DIV>
<DIV><FONT face=Verdana>Graduate Research Assistant</FONT></DIV>
<DIV><FONT face=Verdana>Dept. of Bioengineering</FONT></DIV>
<DIV><FONT face=Verdana>Clemson University, SC- 29631.</FONT></DIV>
<DIV><FONT face=Verdana>Email:<FONT color=#0000ff><U>vraut(at)clemson.edu</U></FONT></FONT></DIV>
<DIV><FONT face=Verdana>Phone: 864-650-1431</FONT></DIV></DIV></DIV></DIV><p><hr SIZE=1>
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