From chemistry-request: at :server.ccl.net Mon Oct 1 03:35:35 2001 Received: from mail2.zrz.tu-berlin.de ([130.149.4.14]) by server.ccl.net (8.11.6/8.11.0) with ESMTP id f917ZZ524503 for ; Mon, 1 Oct 2001 03:35:35 -0400 Received: from mailszrz.zrz.tu-berlin.de ([130.149.4.11]) by mail2.zrz.tu-berlin.de with esmtp (exim-3.33) id 15nxbt-00065c-00; Mon, 01 Oct 2001 09:35:29 +0200 Received: from natrium.chem.tu-berlin.de ([130.149.169.143]) by mailszrz.zrz.tu-berlin.de with esmtp (exim-3.33) id 15nxbs-00043a-00; Mon, 01 Oct 2001 09:35:28 +0200 Mime-Version: 1.0 X-Sender: chwu0531 |-at-| mailszrz.zrz.tu-berlin.de Message-Id: In-Reply-To: <200109301343.f8UDh3529483#* at *#server.ccl.net> References: <200109301343.f8UDh3529483 "-at-" server.ccl.net> Date: Mon, 1 Oct 2001 09:35:28 +0200 To: Denny From: Christoph van =?iso-8859-1?Q?W=FCllen?= Subject: Re: CCL:electron state of LaF? Cc: chemistry: at :ccl.net Content-Type: text/plain; charset="iso-8859-1" ; format="flowed" Content-Transfer-Encoding: 8bit X-MIME-Autoconverted: from quoted-printable to 8bit by server.ccl.net id f917ZZ524504 > >I know the configuration (PI)(PI) can produce 3(Sigma)^(+), 3(Sigma)^(-), ^^^^ >3(Delta). ...for a delta state, you have to put two electrons in a l_z=2 orbital. Two electrons in one orbital, that makes a singlet for me. With the number of alpha electrons exceeding the number of beta electrons by 2, you should look for the triplets only --- 3(Sigma)^(-) ----. +---------------------------------+-------------------------------------+ | Prof. Christoph van Wüllen | Tele-Phone (+49) (0)30 314 27870 | | Technische Universität Sekr. C3 | Tele-Fax (+49) (0)30 314 23727 | | Straße des 17. Juni 135 | eMail | | D-10623 Berlin, Germany | Christoph.vanWullen:~at~:TU-Berlin.De | +---------------------------------+-------------------------------------+ --