From chemistry-request- at -ccl.net Wed May 28 20:19:00 2003 Received: from mail-01.med.umich.edu ([141.214.93.149]) by server.ccl.net (8.12.8/8.12.8) with ESMTP id h4T0J0gC022116 for ; Wed, 28 May 2003 20:19:00 -0400 Received: from gwia-01-MTA by mail-01.med.umich.edu with Novell_GroupWise; Wed, 28 May 2003 20:18:59 -0400 Message-Id: X-Mailer: Novell GroupWise Internet Agent 6.0.2 Date: Wed, 28 May 2003 20:18:42 -0400 From: "Renxiao Wang" To: Subject: A question on heat of formation Mime-Version: 1.0 Content-Type: text/plain; charset=US-ASCII Content-Transfer-Encoding: 7bit Content-Disposition: inline Hi, CCLers! Should the heat of formations of two enantiomers of a chiral compound be identical? I think the answer is yes. Please point out some references for this. A disturbing fact is that, no matter you use QM or MM to calculate the heat of formation for a given molecule, the number is conformation-depentdent. I guess this is because of the steric energy part is conformation-dependent. So, if I really want to compare the stability of two molecules using heat of formation, how may I calculate it right? Best regards, Renxiao Wang renxiao(at)med.umich.edu