Calculation of Quadrupole moments with Gaussian 90
I am using Gaussian90 on the OSC Cray Y-MP to calculate molecular
multipole moments. For benzene, using a 6-31G** basis set, the nonzero
diagonal elements of the quadrupole tensor are as follows:
Qxx -31.2983 Debye-Ang.
Qyy -31.2984
Qzz -39.4673
The molecule is in the standard position, i.e. in the xy-plane, centered
at the origin, with the C6 axis coincident with the z-axis. I've run a
few different basis sets, and the sign and relative magnitudes aren't
affected very much.
For a charge distribution with the symmetry of a benzene molecule,
the quadrupole tensor should be traceless and Qxx = Qyy = -0.5*Qzz.
My question is this: How are the quadrupole moments calculated in
Guassian, and why are the diagonal elements all the same sign and
nearly the same magnitude?
I also have a question about the units. Gaussian reports the quadrupole
moment in units of Debye-Ang. ( Debye-Ang = 10E-18 esu-cm-Ang
= 10E-26 esu-cm-cm.) Experimental results, however, give the benzene
quadrupole moment (Qzz) as -33.3E-40 Coulomb-m-m, which is converted to
-10.0E-26 esu-cm-cm, in a 1980 paper by J. Vrbancich & G.L.D. Ritchie,
J.C.S. Faraday II, 76, 648-649. The results I've been getting from
Gaussian for the quadrupole moments are more consistent with C-m-m than
Debye-Ang. The dipole moments, on the other hand, agree fairly well
(within an order fo magnitude) with experimental results in Debyes.
Any light anyone can shed on this would be greatly appreciated. Thanks!
**********************************************************************
Anne Chaka (216)-368-3699
Dept. of Chemistry
Case Western Reserve University
Cleveland, Ohio 44106
chaka%cwgk.decnet(-(at)-)cwjcc.ins.cwru.edu
**********************************************************************