Sumarry: L



         I summarize for L.  Thank you for everybody.
 From: gaussian.com!fox -x- at -x- lorentzian.com (Doug Fox)
 Subject: Re: L
 To: uunet!dent.okayama-u.ac.jp!ep7%lorentzian.com -x- at -x- uunet.uu.net
 (正村)
 Date: Mon, 8 Jun 1998 11:41:30 -0400 (EDT)
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    Prof. Masamura,
     As I described before nearly linear segments are described as a pair of
 linear bends in place of a valence bend and dihedral which become ill defined
 at the linear  geometry.  These start out as bends in a pair of orthogonal
 reference planes, typically chosen so one is 180.0.  As the molecule optimizes
 the structure may move away from linear and so the two angles are measured
 to remain orthonal, i.e. the reference planes effectively change.
    Clearly this has moved to a nearly 20 degree bend and you should look to
 the cartesian coordinates for these three atoms to get the exact valence
 angle.  One quick way to do this is to read the structure back into G94 with
 %kjob l202
 %chk=mychk
 #  HF ChkBas Geom=AllCheck
 which will stop after evaluating the symmetry and structure printouts for the
 final geometry.  If you have a graphical interface which can read this final
 structure you can use it to measure this angle as well.
 > >optimized
 > >structures.
 > >       Please teach me.
 >
 >         One year ago, I received answer.
 >
 >         For nearly linear segments of a molecule, 175.0 degreees or higher.
 > the possibility exists that the angle will open out to 180 degrees and
 > cause a numerical instability. As a result we define this as a linear angle
 > and include the second, orthogonal bend as well, instead of the deheadral.
 > Thus you will see two entrries with the same trio of atoms labveled
 "L".
 > One should be 180.0 degrees and the other nearly 180.0.
 >
 >         However, I can not understand above.
 > For example,
 >         L(1,12,13)=179.5716
 >         L(1,12,13)=198.5946
 > What is these ?
 >
 >         Please replay to me.
 >
 > Masao Masamura
 > Preventive Dentistry
 > Okayama University Dental School
 > Shikata-cho, 2-5-1
 > Okayama 700
 > Japan
 > FAX: 81-86-235ー6714
 > e-mail: ep7 -x- at -x- dent.okayama-u.ac.jp
 >
   Douglas J. Fox
   Director of Technical Support
   help -x- at -x- gaussian.com
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 Date: Thu, 11 Jun 1998 07:35:21 +0200
 To: ep7 -x- at -x- dent.okayama-u.ac.jp
 From: Per-Ola Norrby <peon -x- at -x- medchem.dfh.dk>
 Subject: Re: CCL:L
 X-UIDL: 5f5e8c83b204b4f86ec59bd9f54629e5
         Dear ??? (I couldn't see your name?)
 >L(4,12,13)=175.0254
 >L(4,12,13)=187.3401     <=== I think L(4,12,13) = D(4,12,13,X) ?
         These are linear bends.  I'm not exactly up to date on the details,
 but I believe that when an angle is close to 180 degrees, you cannot use
 the last dihedral, so instead you use two angles to position "4".
 This
 works, because the program internally keeps track of keeping them
 orthogonal.
 >D(14,13,4,3)=19.8277    <==== I can not understand: A(13,12,4)=180 ?
         You cannot have a dihedral including an angle close to 180, so when
 you have an intervening linear bend, only the first and last atom are used.
         These situations are common with acetylenes and allenes, and also
 with some metals.
         Best regards,
         Per-Ola Norrby
 ^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
 Per-Ola Norrby, peon -x- at -x- medchem.dfh.dk
 Royal Danish School of Pharmacy, Dept. of Med. Chem.
 Universitetsparken 2, DK-2100 Copenhagen, Denmark
 Tel: +45-35376777-506, +45-35370850, fax +45-35370922
 Date: Mon, 15 Jun 1998 11:00:05 +0200
 From: Stefan Fau <fau -x- at -x- ps1515.chemie.uni-marburg.de>
 Reply-To: fau -x- at -x- mailer.uni-marburg.de
 Organization: Philipps-Universit閣 Marburg
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 Hi ep7,
 L-angles are used, when the angle of an atom-triple is close to 180
 degrees. The pair of L-angles belongs to two perpendicular planes (which
 intersect in a line 'parallel' to the atomic triple).
 I can't say anything about your peculiar dihedral angle, but since this
 output seems to be in redundant internal coordinates, there should be
 enough other dihedral angles that are ok.
 Stefan Fau
 Philipps-Universit閣 Marburg
 fau -x- at -x- mailer.uni-marburg.de