CCL: Questions Regarding Orbitals/UV-Visible Absorption && CI
Spaces
- From: "Sina Türeli"
<sinatureli|*|gmail.com>
- Subject: CCL: Questions Regarding Orbitals/UV-Visible Absorption
&& CI Spaces
- Date: Sun, 14 Oct 2007 01:34:31 +0300
You helped me thanks. Though I think that structure of chlorophyll
molecules SHOULD be different in solution or atleast in vacuum, in
terms of steric hinderences which contiributes to Qx. It is the protein
scaffold and the ankorage between the tails of the chlorophylls that
gives the chlorophyll ring a slightly more strained form. When
optimized in vacuum Qx, as I expected, drops down to about 650 (which I
assume is no more qx?).
Although ofcourse vacuum would give a more different structure than
that would have been in solution, but chlorophylls arent in solution in
their local enviroment neither. And also doing semiempirical
calculations with a chlorophyll in water molecules would be very time
demanding. That is, if I do not grossly over estimate it by saying that
it is a 1:1 solution and optimize a chlorophyll molecule with a water
molecule as a ligand to its central MG atom. This ofcourse does not
simulate the effect of the water on the hydrophobic parts of the
chlorophyll and the ring which I assume is the main contributer to Qx
along with interraction of N orbitals with conjugated pi orbitals.
And also as you said, I am more interested in changes in spectra
values rather than their exact values though your message and several
other sources have been helpful for me to select a CI space (which I
guess will be 10,10).
And also have you any ideas on how to make logical connections between
nitrogen orbital shapes, localizations with changes in spectra? As far
as I know, such a high UV absorbance (around 800) needs to involve
transtion from a N orbital to conjugated pi orbitals...
Thanks a lot for your answers.
On
10/11/07, Igor Avilov avilovi{}averell.umh.ac.be
<
owner-chemistry _ ccl.net> wrote:
Sent to CCL by: "Igor Avilov" [avilovi::averell.umh.ac.be]
Dear
Sina,
The 4-orbital model is often used to explain the trends in the
spectra
of tetrapyrrolic compounds. It is based on the fact that in many cases 2
HOMOs and 2 LUMOs are separated from the lower/higher energy orbitals
by
the considerable energy gaps. Thus, one-electron excitation
between
these 4 frontier MOs are likely to play a dominant role in the
formation
of the lowest transitions in the absorption spectrum. But it does
not
mean that the other one-electron excited configurations cannot mix
with
them. This admixture is larger, of cause, for the B-states, as they have
higher energy than the Q-states. So one must use a sufficiently
large
basis for CI calculations. On my personal experience, 10 HOMOs x
10
LUMOs is enough for the calculation of the excited states of
the
porphyrin monomers. If you will use minimal bases like 2 HOMOs x 2 LUMOs
(4-orbital model), you could get into trouble even if you are
interested
only in the several lowest excited states. By the way, I suspect
that in
this basis you would get the energies of the B-states completely
wrong
(even if the energies of the Q-states seem to be good). Once I
performed
such calculations (with 2 x 2 basis) and at the end I had to
simply
throw away the results.
The fact that semi-empirical methods
like CNDO/S and INDO/S give the
energy of the Q-states lower than the experimental values, it's not
a
big problem, on my opinion. What is important - is to get the
trends
right, and here the semi-empirical methods do a very nice job. TD-DFT,
for example, also does not assure quantitative agreement with
the
experiment (look at the paper of D. Sundholm
"A
density-functional-theory study of bacteriochlorophyll b",
PHYSICAL
CHEMISTRY CHEMICAL PHYSICS 5 (19): 4265-4271 OCT 1 2003).
On my opinion you can use the structure from the pdb-file
(containing
the experimental crystal structure of the molecule, I suppose),
although
in solution your molecule may have slightly different geometry. The
results should not be dramatically different if you perform
geometry
optimization first. Anyway, the most important thing is not to
get
theoretical spectrum very-very close to the experimental one,
which
could be (or even usually is) just due to the lucky cancellation of
errors.
I hope I helped you a little bit...
Igor
Avilov.
-----Original Message-----
> From:
owner-chemistry(0)ccl.net [mailto:
owner-chemistry(0)ccl.net]
Sent: jeudi 11 octobre 2007 12:40
To: Igor Avilov
Subject: CCL: Questions
Regarding Orbitals/UV-Visible Absorption && CI
Spaces
Sent
to CCL by: "Sina T reli" [sina.tureli,
boun.edu.tr]
I have some questions regarding qualitative reasoning
about how to
corralate orbital localizations with uv-visible absorption and
also size
CI spaces to be used in detecting the bands of
bacteriochlorophylls.
1. It is known that bacteriochlorophylls usually have qx bands
around
700-800nm. And that can be accounted to effect of both conjugation
and
the jumping of electrons from nitrogen orbitals to the conjugated pi
orbitals of the system. How ever still knowing that I am not able
to
qualitatively reason on how the orbitals localization and size
effect
the osscilator strength and absorption. Given below are the
orbitals
that contirbute to the Qx (830nm) of bacteriochlorophyll a. The
transition
L->H is the dominant one. This calculation is performed on
the
nonoptimized chlorophyll taken from a pdb with arguslab using (5,5)
CI space.
The qx absorbance was seen to be about 833 nm. So in short,
why would the third transition be the one with the higher
oscillator
strength or why would these orbitals specifically contirbute to
830nm
absorbance, how can be make qualitative reasoning
about
orbital-absorbance relatedness. Any sources of study as an answer is
also welcome.
http://img518.imageshack.us/img518/4318/qyyc5.jpg
2. In literature
and in some discssions that Mark Thompson (creator of
the arguslab program) has participated in this list, it is said that a
CI space of (20,20) is optimal for such large molecules... But
20,20
gives about 950 nm while 5,5 gives about 830 nm (which is very
close).
And also according to the four orbital model (which can also
be
visiualized by plotting the energies of the orbitals), 4,4 CI space
shuld be enough to visiualize the Qx reagion, shouldnt it be? Keep
in
mind that I performed the calculations only the chlorophyll not
the
whole complex.
3. Finally, would performing CI calculations on
a chlorophyll taken
directly from pdb give reliable results or would some kind
of
optimization of the chlorophyll molecule required to get
reliable
results?
Thanks for your kind answers...
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