CCL: why is there no 2d subshell in atoms



Hi William,

Thanks for your response. I think that answers my question.

Tom


On Thu, Dec 24, 2020 at 9:49 AM William F. Polik polik#%#hope.edu <owner-chemistry###ccl.net> wrote:
Oops, typo!  I meant Laguerre polynomial, not Legendre function.  I should have written:

Mathematically, the 1-electron Coulombic (eg, H-atom) wavefunction has:
  * l angular nodes that arise from the associated Legendre function Y^m_l (a polynomial of order l) in the angular part of the wavefunction
  * n-l-1 radial nodes that arise from the associated Laguerre polynomial L^(2l+1)_(n+l) (a polynomial of order n-l-1) in the radial part of the wavefunction
 
If l > n-1 (eg, 2d for which n=2 and l=2) , then the associated Laguerre polynomial L^(2l+1)_(n+l) is undefined (qualitatively it would have a negative number of nodes, which is unphysical).

So it is the Laguerre polynomial in the wavefunction arising from the 1-electron Coulombic potential that enforces l < n.

Will

On 12/23/20 11:26 AM, William F. Polik wrote:
Tom,

The node argument very appealing.  Here is a mathematical basis for it.

Mathematically, the 1-electron Coulombic (eg, H-atom) wavefunction has:
  * l angular nodes that arise from the associated Legendre function Y^m_l (a polynomial of order l) in the angular part of the wavefunction
  * n-l-1 radial nodes that arise from the associated Legendre function L^(2l+1)_(n+l) (a polynomial of order n-l-1) in the radial part of the wavefunction
 
If l > n-1 (eg, 2d for which n=2 and l=2) , then the associated Legendre function L^(2l+1)_(n+l) is undefined (qualitatively it would have a negative number of nodes).

So it is the Legendre function arising from the 1-electron Coulombic potential wavefunction that enforces l < n.

One could probably reference almost any quantum mechanical or quantum chemistry textbook that provides sufficient detail into the derivation of the H-atom wavefunction for this.

Will


On 12/23/20 3:46 AM, Jan Halborg Jensen jhjensen**chem.ku.dk wrote:
Sent to CCL by: Jan Halborg Jensen [jhjensen~!~chem.ku.dk]
 Dear Tom
 One way to think about it is that the principal quantum number n is related to
 the number of nodes of the AO: number of nodes = n-1. The minimum number of
 nodes in a d-orbital is 2 (you can’t have a d-orbital shape without 2
 nodes). So the minimum value of n for d-orbitals is 3.
 So why is the number of nodes related to n? One way to think about n, at least
 for the H atom, is in terms of the orbital energies: orbitals with the same
 energy have the same n. In other words the energy of the electron is a function
 of the number of nodes. The nodes increase the energy because they cause the
 electron to be further away from the nucleus (on average). The nodes are there
 to keep the orbitals orthogonal so that the Pauli exclusion (i.e. anti-symmetry)
 principle is satisfied, among other things.
 Hope this helps.
 Best regards, Jan
 
On 23 Dec 2020, at 04.53, Thomas Manz thomasamanz++gmail.com
 <owner-chemistry::ccl.net> wrote:
 Dear colleagues,
 I am looking for a reference to cite that provides mathematical details as to
 why a 2d subshell does not exist for an atom. I understand the traditional pat
 answer that n >= L+1 where L is angular quantum number ( L = 0 for s, 1 for
 p, 2 for d, etc.) and n is the principal quantum number. I would like to
 understand the mathematical and physical reason for this, preferably with some
 kind of mathematical derivation. Does anyone know a good reference for this?
 Although the above question seems "simple", I believe there more to it
 than first meets the eye. Specifically, such a rule does not apply to the
 nucleons inside an atomic nucleus. In nuclear models (e.g., nuclear shell
 model), for example, they encounter things such as the 1f orbitals. Why does
 such an orbital exist for nucleons but not for electrons, when both are spin 1/2
 fermions? The physical interaction (coupling regime) must have something to do
 with whether or not the 1f orbital exists for a particular fermion. In the case
 of nucleons, there is a very strong pairing so that two nucleons practically
 pair to make an effective boson; however, it is my understanding that for
 nucleons with odd-numbered nucleons, the odd nucleon can still exist in orbitals
 such as 1f. The spin-orbit coupling is substantial for nucleons, but also
 substantial for electrons in heavy elements.
 I would appreciate any mathematical or physical insights as well references to
 understand what is going on here.
 Sincerest thanks,
 Tom Manz
 
CHEMISTRY|-|ccl.net or use:
       http://www.ccl.net/cgi-bin/ccl/send_ccl_message
 E-mail to administrators: CHEMISTRY-REQUEST|-|ccl.net or use
       http://www.ccl.net/cgi-bin/ccl/send_ccl_messagehttp://www.ccl.net/chemistry/sub_unsub.shtml
 Before posting, check wait time at: http://www.ccl.net
 Job: http://www.ccl.net/jobs
 Conferences: http://server.ccl.net/chemistry/announcements/conferences/
 Search Messages: http://www.ccl.net/chemistry/searchccl/index.shtmlhttp://www.ccl.net/spammers.txt
 RTFI: http://www.ccl.net/chemistry/aboutccl/instructions/
 .
 

--

Dr. William F. Polik
Hofma Professor of Chemistry

Department of Chemistry
Schaap Science Center 2122
Hope College
35 East 12th Street
Holland, MI  49422-9000
USA

polik|-|hope.edu
http://www.chem.hope.edu/~polik
tel: (616) 395-7639
fax: (616) 395-7118


--

Dr. William F. Polik
Hofma Professor of Chemistry

Department of Chemistry
Schaap Science Center 2122
Hope College
35 East 12th Street
Holland, MI  49422-9000
USA

polik|-|hope.edu
http://www.chem.hope.edu/~polik
tel: (616) 395-7639
fax: (616) 395-7118